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MrRissso [65]
3 years ago
7

Pls help with number 2 will give brainliest

Mathematics
1 answer:
Law Incorporation [45]3 years ago
6 0

Answer:41% i think i am pretty sure


Step-by-step explanation:

don't have one

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A rectangle has a length of (x+5)and a with of x Write down the expression for the area of a rectangle If the area is 24cm²,find
ratelena [41]

Answer: Width = 3cm

Length = 8cm

Step-by-step explanation:

Length = x+5 cm

Width = xcm

Area = 24cm²

Area of a rectangle = length × width

x × (x + 5) = 24

x² + 5x = 24

x² + 5x - 24 = 0

x² + 8x - 3x - 24 = 0

x(x + 8) - 3(x + 8) = 0

x - 3 = 0

x = 3

Width = 3cm

Since length = x + 5 = 3 + 5 = 8cm

Length = 8cm

8 0
3 years ago
A music store gives every 20th customer A $5 gift card. Every 50th customer gets A $10 gift card. Which customer will be the fir
slavikrds [6]
The 100th customer would be the first to receive both.
20×5=100
50×2=100
3 0
3 years ago
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What is the measure of AngleJHG?
Doss [256]
There is no attachment so we don’t know what this angle is.
5 0
3 years ago
If the sides of a triangle have the following lengths, find a range possible values for x
makvit [3.9K]

Answer:

9.5 < x < 15

Step-by-step explanation:

4 0
2 years ago
If the original square had a side length of
irina [24]

Answer:

Part a) The new rectangle labeled in the attached figure N 2

Part b) The diagram of the new rectangle with their areas  in the attached figure N 3, and the trinomial is x^{2} +11x+28

Part c) The area of the second rectangle is 54 in^2

Part d) see the explanation

Step-by-step explanation:

The complete question in the attached figure N 1

Part a) If the original square is shown below with side lengths marked with x, label the second diagram to represent the new rectangle constructed by increasing the sides as described above

we know that

The dimensions of the new rectangle will be

Length=(x+4)\ in

width=(x+7)\ in

The diagram of the new rectangle in the attached figure N 2

Part b) Label each portion of the second diagram with their areas in terms of x (when applicable) State the product of (x+4) and (x+7) as a trinomial

The diagram of the new rectangle with their areas  in the attached figure N 3

we have that

To find out the area of each portion, multiply its length by its width

A1=(x)(x)=x^{2}\ in^2

A2=(4)(x)=4x\ in^2

A3=(x)(7)=7x\ in^2

A4=(4)(7)=28\ in^2

The total area of the second rectangle is the sum of the four areas

A=A1+A2+A3+A4

State the product of (x+4) and (x+7) as a trinomial

(x+4)(x+7)=x^{2}+7x+4x+28=x^{2} +11x+28

Part c) If the original square had a side length of  x = 2 inches, then what is the area of the  second rectangle?

we know that

The area of the second rectangle is equal to

A=A1+A2+A3+A4

For x=2 in

substitute the value of x in the area of each portion

A1=(2)(2)=4\ in^2

A2=(4)(2)=8\ in^2

A3=(2)(7)=14\ in^2

A4=(4)(7)=28\ in^2

A=4+8+14+28

A=54\ in^2

Part d) Verify that the trinomial you found in Part b) has the same value as Part c) for x=2 in

We have that

The trinomial is

A(x)=x^{2} +11x+28

For x=2 in

substitute and solve for A(x)

A(2)=2^{2} +11(2)+28

A(2)=4 +22+28

A(2)=54\ in^2 ----> verified

therefore

The trinomial represent the total area of the second rectangle

7 0
3 years ago
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