If you plot the points given on a coordinate plane you see that this is a hyperbola that is is horizontal in nature, meaning it opens side to side, not up and down. We can determine the center of it by taking the point equidistant from the vertices, which is (4, 5), the h and k of our center, respectively. Also, the equation looks like this when it is horizontal:
. a is the distance between the center and the vertices, so our a = 2, and c is the distance between the center and the foci, so our c = 3. We need to find b now, using Pythagorean's theorem.
and
. Now we have everything we need to rewrite the equation:
I think it means to write that in slope intercept form. there for, it’ll be y=8x+23. hope this helps
The surface charge density:
S(igma) = Q / A
A = 1.6 * 10^(-2) * 1.6 * 10^(-2) = 2.56 * 10^(-4) m²
The electric field: E = S / E(psilon) o
E = 0.711 * 10^^(-9) / ( 2.56 * 10 ^(-4) * 8.85 * 10 ^(-12) ) =
= 0.3138 * 10 ^6 = 3.138 * 10^5 V/m
a ) Δ V = E d
Δ V = 3.138 * 10^5 V/m* 1.2 * 10^(-3) m = 376.56 V
b ) When d = 2.40 mm:
Δ V = 3.138 * 10^5 V/m * 2.40 *10^(-3) m = 753.12 V
Answer:
See Below
Step-by-step explanation:
We are given 3 equations.
3x + 8
5x - 20
and
5x + 4y
First lets solve for x using the first two
3x + 8 = 5x -20
Move the variables to one side
3x + 8 = 5x -20
-3x -3x
8 = 2x -20
+20 +20
28 =2x
28/2 =2x /2
14 = x
Now we have x = 14
Lets plug this into the second equation to solve for the angle
3(14) + 8
42 + 8 = 50
5(14) - 20
70 - 20 =50
Now, lets plug the x and the angle into the third equation to find y
5 (14) +4y = 50
70 + 4y = 50
-70 -70
4y = -20
4y/4 = -20/4
y = -5
So now we have:
x = 14
y = -5
and the angle = 50
Hope this helps!
