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givi [52]
3 years ago
11

I need help with number 13. Both letters please Thank you for any help!

Mathematics
1 answer:
insens350 [35]3 years ago
6 0

A. (24-3)/8 (I'm not 100% sure this answer is correct because I cant remember what an inequality is)

B. You should buy three packages because it would be better to have some left over than to not have enough (I know this answer is correct)

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Help! Please no links or I will report u!!
yawa3891 [41]

Answer:

D

Step-by-step explanation:

The range is all of the y values that make a function true. Our graph here starts at y=-2 and then goes up for infinity. This means the range is y ≥ -2. The domain is [0, ∞) because our x values start at 0 and go to infinity. This means the domain is restricted so A is not true, B is not true because the graph does not exist at x = -2.

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3 years ago
Helppppppppppppppppppppppppppppp
mafiozo [28]

Answer:

1.) x=3  2.)n= -1/4 3.) h=7

Step-by-step explanation:

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3 years ago
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0.2x - 1 = -1<br> Fndndndnddsmsmsskaalamakaksnsndnx c cncjxmdnd
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Answer:

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Step-by-step explanation:

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3 years ago
A square has a diagonal of length 12. Find the length of each side.
White raven [17]

Answer:

3

Step-by-step explanation:

12÷4=3

Hope this will help you!

7 0
3 years ago
A right pyramid with a regular hexagon base has a height of 3 units If a side of the hexagon is 6 units long, then the apothem i
Setler79 [48]

Answer:

Part a) The slant height is 3\sqrt{2}\ units

Part b) The lateral area is equal to 54\sqrt{2}\ units^{2}

Step-by-step explanation:

we know that

The lateral area of a right pyramid with a regular hexagon base is equal to the area of its six triangular faces

so

LA=6[\frac{1}{2}(b)(l)]

where

b is the length side of the hexagon

l is the slant height of the pyramid

Part a) Find the slant height l

Applying the Pythagoras Theorem

l^{2}=h^{2} +a^{2}

where

h is the height of the pyramid

a is the apothem

we have

h=3\ units

a=3\ units

substitute

l^{2}=3^{2} +3^{2}

l^{2}=18

l=3\sqrt{2}\ units

Part b) Find the lateral area

LA=6[\frac{1}{2}(b)(l)]

we have

b=6\ units

l=3\sqrt{2}\ units

substitute the values

LA=6[\frac{1}{2}(6)(3\sqrt{2})]=54\sqrt{2}\ units^{2}

3 0
3 years ago
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