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Sloan [31]
3 years ago
11

PLEASE HELP QUICK, I NEED IT

Mathematics
2 answers:
just olya [345]3 years ago
5 0
We take the equation <span>d = -16t^2+12t</span> and subtract d from both sides to get
                                         0<span> = -16t^2+12t - d
We apply the quadratic formula to solve for t. With a = -16, b = 12, c = -d, we have
                                         t = [ -(12) </span><span>± √( 12^2 - 4(-16)(-d) ) ] / [2 * -16]</span>
                                           = [- 12 ± √(144-64d) ] / (-32)
                                           = [- 12 ± √16(9-4d)] / (-32)
                                           = [- 12 ± 4√(9-4d)] / (-32)
                                           = 3/8 ±√(9-4d) / 8
The answer to your question is t = 3/8 ±√(9-4d) / 8
guajiro [1.7K]3 years ago
3 0

Here are a bunch of CORRECT answers. Your answer is in the last pic. I got number 3 wrong, but it still showed the correct answer.

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5n + 3n<br> simplify each expression
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Answer: 8n

Step-by-step explanation: 5n + 3n

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Solve the inequality 3(x + 2) &gt; 0.
Murljashka [212]

Answer:

B.) x>-2

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3 years ago
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Given the polynomial 6x3 + 4x2 − 6x − 4, what is the value of the constant 'k' in the factored form? 6x3 + 4x2 − 6x − 4 = 2(x +
CaHeK987 [17]
First you graph it using a graphing calculator, you look at the table of values to find out one point in which y= 0. The first one that comes up is when x=1.
If you don't have a graphing calculator you can use trial and error by inputing some numbers into x until you get y= 0. 

Once you have an x value which makes y=0, you can start factorizing it. 
you divide 6x3 +4x2 -6x - 4 into (x-1) which is when y =0 
to get 6x2+10x+4 

This can be used to write the polynomial as (x-1)(6x2 +10x+4) 
you then factorize the second bracket, 6x2 +10x+4.
you can take the 2 outside to give you 2(3x2 +5x+2) 
you can factorize this to become 2(3x+2)(x+1) 

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7 0
3 years ago
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A student had 500 milliliters of water in a water bottle. She drank 25% of the water before soccer practice. After practice, she
marta [7]

A student had 500 milliliters of water in a water bottle. She drank 25% of the water before soccer practice. After practice, she drank 1/3 of the remaining water.

​How much water, in milliliters, does the student have left in the bottle?

Answer:

the amount of water the student have left in the bottle is 250 milliliters

Step-by-step explanation:

A student had 500 milliliters of water in a water bottle. She drank 25% of the water before soccer practice. After practice, she drank 1/3 of the remaining water.

​How much water, in milliliters, does the student have left in the bottle?

Before the soccer practice, she drank 25 % of the water

25% of the water = 25% of 500

                             = 25% × 500

                              =\frac{25}{100} ×  500

At the right hand-side of the equation, the two zeros will cancel-out the other two zeros, hence;

                                = 25 × 5

                                 =125

25% of the water = 125 milliliters

From the question, it was said that drank 25% of the water before soccer, this implies that she drank 125 milliliters from the water bottles.

If she drank 125 milliliters of  from a 500 milliliters water contain in the water bottle, then the amount of water left will be 500 ml - 125 ml = 375 ml

This implies that before the soccer practice she had 375 milliliters of water left in the water bottle.

After the practice, she drank 1/3 of the remaining water, which means after the practice she drank 1/3 of 375

1/3 of 375 = \frac{1}{3} × 375 = \frac{375}{3} = 125

After the practice she drank 125 milliliters of water from her 375 milliliters water.

The amount of water she have left after the practice will be;

375 milliliters - 125 milliliters = 250 milliliters

Therefore, the amount of water the student have left in the bottle is 250 milliliters

8 0
3 years ago
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Lelechka [254]

Answer:

4

Step-by-step explanation:

6 0
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