Question

Please help asap 25 pts

Answer 1

$y=ax^2+bx+c\\\\\text{Axis of symmetry:}\ x=\dfrac{-b}{2a}$


$\text{We have:}\\\\y=4x^2+16x-18\\\\a=4;\ b=16;\ c=-18\\\\x=\dfrac{-16}{2\cdot4}=\dfrac{-16}{8}=-2$

Answer: A.