I'm calculated and I figure that it's graphing
Answer:
1680 possible pizzas
Step-by-step explanation:
Pizza contains 2 different meat and 3 different vegetables.
If there are 5 meats and 8 vegetables, the customer can select any one of 3 types of crust.
Total number of ways to select meat = 5C2
nCr = n! /(n-r)! r!
5C2 = 5! / (5-2)!2!
= 5! / 3!2!
= 10
Total number of ways to select vegetables = 8C3
= 8!/(8-3)!3!
= 8! / 5!3!
= 56
Total number of pizza choice that can be made = 3 * 5C2 * 8C3
= 3*10*56
= 1680 possible pizza
Answer:2.87
Step-by-step explanation:
Answer:
Option D is right,.
Step-by-step explanation:
-a+4b+2c=-8 ... i
3a+b-4c=9 ... ii
b=-1 ... iii
Substitute the value of b, in i and ii
-a-4+2c =-8 or -a+2c = -4
and 3a-1-4c = 9 or 3a -4c =8
Now we have two equations in two variables
-a+2c =-4 and 3a-4c =8
a = 2c+4: substitute this in the other equatin.
3(2c+4)-4c =8 Or 2c +12 =8
2c =-4 or c = -2
Substitute in -a+2c =12
-a-2 = -4
a = -2+4 =2
a=2, b=-1 and c =-1 is the solution.
