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alexira [117]
3 years ago
10

Mark is in training for a bicycle race. He needs to ride 50 kilometers a week as part of his training. He rode 18.23 kilometers

on Monday and 13.94 kilometers on Wednesday. How much more does Mark need to ride to complete his training for the week. will mark brainly
Mathematics
1 answer:
kirill115 [55]3 years ago
7 0

the answer is B-about 18km


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Shoe sizes for men in the United States are known to follow a normal distribution. If you calculated the z-score of a man's shoe
anastassius [24]

Answer:

This value means that his shoe size is 2.9 deviations above the population mean.

And we can find the approximate percentile for his measure like this:

P(Z

This correspond to the 99.8 percentile, so then his shoe size is 99.8% above all the shoe sizes.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the shoe size of a population, and for this case we know the distribution for X is given by:

X \sim N(\mu,\sigma)  

Where \mu represent the mean and \sigma the population standard deviation.

For this case we know that a man obtain a z score of z=2.9

This value means that his shoe size is 2.9 deviations above the population mean.

And we can find the approximate percentile for his measure like this:

P(Z

This correspond to the 99.8 percentile, so then his shoe size is 99.8% above all the shoe sizes.

3 0
3 years ago
Can you guys help again
dangina [55]

Answer:

Step-by-step explanation:

1 = 27

2 = 36

2 = 1,000

3 0
3 years ago
Read 2 more answers
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stellarik [79]

Since the number of cats has to be less than 28, a statement could be "the shelter can house no more than 28 cats.

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3 years ago
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