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2 years ago

Can someone please help me out Its really Important please marking brainliest Answer what you can

Mathematics

1 answer:

Marianna [84]2 years ago

6 0

Answer:

a rectangular prism is simply a block. it has length, width and height. and similar to the area of a rectangle (length×width) we get as volume length×width×height.

other than that we only need to consider that a volume always has cubic units (like cm³, m³, ft³, ...).

the volume of a cylinder is again ground area times height, when we imagine the cylinder to stand on it circular side.

and the states standard formula (hi, internet !) for the volume of a cylinder is pi×r²×height

so, we have 75×20×14 = 21,000 cm³

and pi×75²×120 = pi×5625×120 = 2,120,575 cm³

so, the cylinder has a much bigger volume.

3.a.

the standard formula for the volume of a pyramid (hi, internet !) is length×width×height/3

the diagram means that it is a square pyramid (the ground area is a square). therefore all sides of the ground area are of equal length. length = width

so, we have 64×64×40/3 = 54631.333... m³

3.b.

as the description says, 5000 people fit in, so, to find how much volume is there available per person, we need to divide the volume by 5000.

54631.333... / 5000 = 10.923 m³

Step-by-step explanation:

and again, you need only to search the formulas on the internet, and then calculate this with the given numbers yourself, and you will be much faster than paying things here and waiting for answers and copy/pasting things.

again, there is practically nothing to explain, just to use the standard formulas and the calculator. what's the problem ?

I will gladly explain to you concepts you have not understood (that is the point of Brainliest). but I and others here are not your personal slaves to do your work for you.

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At 2:00 PM a car's speedometer reads 30 mi/h. At 2:20 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:20 the acce

Bad White [126]

Answer:

Let v(t) be the velocity of the car t hours after 2:00 PM. Then $\frac{v(1/3)-v(0)}{1/3-0}=\frac{50 \:{\frac{mi}{h} }-30\:{\frac{mi}{h} }}{1/3\:h-0\:h} = 60 \:{\frac{mi}{h^2} }$ . By the Mean Value Theorem, there is a number c such that $0 < c$ with $v'(c)=60 \:{\frac{mi}{h^2}}$ . Since v'(t) is the acceleration at time t, the acceleration c hours after 2:00 PM is exactly $60 \:{\frac{mi}{h^2}}$ .

Step-by-step explanation:

The Mean Value Theorem says,

Let be a function that satisfies the following hypotheses:

f is continuous on the closed interval [a, b].
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Then there is a number c in (a, b) such that

$f'(c)=\frac{f(b)-f(a)}{b-a}$

Note that the Mean Value Theorem doesn’t tell us what c is. It only tells us that there is at least one number c that will satisfy the conclusion of the theorem.

By assumption, the car’s speed is continuous and differentiable everywhere. This means we can apply the Mean Value Theorem.

Let v(t) be the velocity of the car t hours after 2:00 PM. Then $v(0 \:h) = 30 \:{\frac{mi}{h} }$ and $v( \frac{1}{3} \:h) = 50 \:{\frac{mi}{h} }$ (note that 20 minutes is $20/60=1/3$ of an hour), so the average rate of change of v on the interval $[0 \:h, \frac{1}{3} \:h]$ is

$\frac{v(1/3)-v(0)}{1/3-0}=\frac{50 \:{\frac{mi}{h} }-30\:{\frac{mi}{h} }}{1/3\:h-0\:h} = 60 \:{\frac{mi}{h^2} }$

We know that acceleration is the derivative of speed. So, by the Mean Value Theorem, there is a time c in $(0 \:h, \frac{1}{3} \:h)$ at which $v'(c)=60 \:{\frac{mi}{h^2}}$ .

c is a time time between 2:00 and 2:20 at which the acceleration is $60 \:{\frac{mi}{h^2}}$ .

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