Fraction of students enrolled in Chinese = 
Fraction of students enrolled in French = 
Fraction of students enrolled in Spanish = 
Solution:
Total number of students = 51 + 33 + 42
= 126
Number of students enrolled in Chinese = 51
Fraction of students enrolled in Chinese
Fraction of students enrolled in Chinese =
Number of students enrolled in French = 33
Fraction of students enrolled in French
Fraction of students enrolled in French =
Number of students enrolled in Spanish = 42
Fraction of students enrolled in Spanish
Fraction of students enrolled in Spanish =
Step-by-step explanation:
<h3><u>Given</u><u>:</u><u>-</u></h3>
(√3+√2)/(√3-√2)
<h3><u>To </u><u>find</u><u>:</u><u>-</u></h3>
<u>Rationalised</u><u> form</u><u> </u><u>=</u><u> </u><u>?</u>
<h3><u>Solution</u><u>:</u><u>-</u></h3>
We have,
(√3+√2)/(√3-√2)
The denominator = √3-√2
The Rationalising factor of √3-√2 is √3+√2
On Rationalising the denominator then
=>[(√3+√2)/(√3-√2)]×[(√3+√2)/(√3+√2)]
=>[(√3+√2)(√3+√2)]×[(√3-√2)(√3+√2)]
=>(√3+√2)²/[(√3-√2)(√3+√2)]
=> (√3+√2)²/[(√3)²-(√2)²]
Since (a+b)(a-b) = a²-b²
Where , a = √3 and b = √2
=> (√3+√2)²/(3-2)
=> (√3-√2)²/1
=> (√3+√2)²
=> (√3)²+2(√3)(√2)+(√2)²
Since , (a+b)² = a²+2ab+b²
Where , a = √3 and b = √2
=> 3+2√6+2
=> 5+2√6
<h3><u>Answer:-</u></h3>
The rationalised form of (√3+√2)/(√3-√2) is 3+2√6+2.
<h3>
<u>Used formulae:-</u></h3>
→ (a+b)² = a²+2ab+b²
→ (a-b)² = a²-2ab+b²
→ (a+b)(a-b) = a²-b²
→ The Rationalising factor of √a-√b is √a+√b
Answer: x^4
Step-by-step explanation:
1. Rewrite the expression in fraction form:
(3√x²)^6 = x^(2/3)^6
2 is the exponent, so when written in fraction form, it is the numerator. 3 is the index or root, so in fraction form it is the denominator.
2. Solve:
x^(2/3)^6 = x^(12/3) = x^4
Because the exponent 2/3 is raised to the power of 6, you can use the power rule, which basically just means that whenever an exponent is raised to an exponent, multiply them. So, 2/3 * 6 equals 12/3, and 12/3 equals 4, making your answer x^4.
Answer:
The answer would be 3/16
Step-by-step explanation:
Total no.of beads = 16
No.of blue beads = 3
Probability of picking a blue bead = 3/16
Answer:
Take the slopes, such that 7-4/-4+3= 3/-1=-3
So one endpoijt is (-5,10)
