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2 years ago

14

paul bought a student discount card for the bus. the card allows him to buy daily bus passes for $1.50. after one month paul bou

ght 15 passes and spent a total of $29.50. how much did he spend on the student discount card?

1 answer:

anastassius [24]2 years ago

4 0

D= cost of discount card
29.50 = d + 1.50(15)
29.50 = d + 22.50
<u>-22.50 -22.50
</u> $7.00 = d
<u /> d = $7

Paul spent $7 dollars on the discount card.

Hope this helped :D.

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Answer:

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Step-by-step explanation:

Given

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$T_7 = 40$

Required

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To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

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Divide the 7th term by the 5th term; This gives

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Divide the numerator and the denominator of the fraction by 40

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Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

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By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

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$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

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$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

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$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

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$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

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Step-by-step explanation:

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Therefore, m∠F = 50°

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So, both the triangles have congruent corresponding angle measures.

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