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inysia [295]
3 years ago
5

I need help plss dont lieplss and thank you

Mathematics
1 answer:
forsale [732]3 years ago
4 0

Answer:

B or C

hope this helps :)

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laptop screen sizes are determines by the diagonal measurement rounded to the nearest whole number a laptop screen has a 9 in wi
Delvig [45]
------------------------------------------------------------------------------------------
Formula
------------------------------------------------------------------------------------------
a² + b² = c²

------------------------------------------------------------------------------------------
Find Diagonal
------------------------------------------------------------------------------------------
9² + 7² = c²
c² = 81 + 49
c² = 130
c = 11 in (Nearest whole number)

------------------------------------------------------------------------------------------
Answer: The diagonal measure 11 inches
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6 0
3 years ago
Please help me to solve this problem<br>​
faust18 [17]

Answer:

\sqrt{3} + \frac{5\sqrt{3} }{6}

Step-by-step explanation:

tan(30°) = \frac{\sqrt{3}}{3}

cot(30°) = \sqrt{3}

sin(60°) = \frac{\sqrt{3}}{2}

\frac{\sqrt{3} }{3} +\sqrt{3} +\frac{\sqrt{3}}{2}  = \sqrt{3} +\frac{5\sqrt{3} }{6}

3 0
2 years ago
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A^3+a+a^2+1 2a^2+2ab+ab^2+b^3
Vikentia [17]
\frac{a^3+a+a^2+1}{a^3+a^2+ab^2+b^2} \cdot  \frac{2a^2+2ab+ab^2+b^3}{a^3+a+a^2b+b} =\frac{a(a^2+1)+1(a^2+1)}{a^2(a+1)+b^2(a+1)} \cdot  \frac{2a(a+b)+b^2(a+b)}{a(a^2+1)+b(a^2+1)} =\\\\=\frac{(a^2+1)(a+1)}{(a+1)(a^2+b^2)} \cdot  \frac{(a+b)(2a+b^2)}{(a^2+1)(a+b)} = \frac{2a+b^2}{a^2+b^2}
6 0
3 years ago
How are the triangles similar pleaseee help I’ll give you BRAINLIEST
Bad White [126]

Answer:

SSS

Step-by-step explanation:

Only sides are given, not angles, so you know it's side-side-side

7 0
3 years ago
Determine the most precise name for ABCD (parallelogram, rhombus, rectangle, or square). Explain how you determined your answer.
Sonja [21]
<h3>Answer:  Rhombus</h3>

======================================================

Reason:

Let's find the distance from A to B. This is equivalent to finding the length of segment AB. I'll use the distance formula.

A = (x_1,y_1) = (3,5) \text{ and } B = (x_2, y_2) = (7,6)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(3-7)^2 + (5-6)^2}\\\\d = \sqrt{(-4)^2 + (-1)^2}\\\\d = \sqrt{16 + 1}\\\\d = \sqrt{17}\\\\d \approx 4.1231\\\\

Segment AB is exactly \sqrt{17} units long, which is approximately 4.1231 units.

If you were to repeat similar steps for the other sides (BC, CD and AD) you should find that all four sides are the same length. Because of this fact, we have a rhombus.

-------------------------

Let's see if this rhombus is a square or not. We'll need to see if the adjacent sides are perpendicular. For that we'll need the slope.

Let's find the slope of AB.

A = (x_1,y_1) = (3,5) \text{ and } B = (x_2,y_2)  = (7,6)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{6 - 5}{7 - 3}\\\\m = \frac{1}{4}\\\\

Segment AB has a slope of 1/4.

Do the same for BC

B = (x_1,y_1) = (7,6) \text{ and } C = (x_2,y_2)  = (6,2)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{2 - 6}{6 - 7}\\\\m = \frac{-4}{-1}\\\\m = 4\\\\

Unfortunately the two slopes of 1/4 and 4 are not negative reciprocals of one another. One slope has to be negative while the other is positive, if we wanted perpendicular lines. Also recall that perpendicular slopes must multiply to -1.

We don't have perpendicular lines, so the interior angles are not 90 degrees each.

Therefore, this figure is not a rectangle and by extension it's not a square either.

The best description for this figure is a <u>rhombus</u>.

4 0
2 years ago
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