Answer:
<h2>x = 14, z = 65</h2>
Step-by-step explanation:
The angles (5x - 5)° and (6x + 31)° are supplementary angles.
Supplementary Angles add up to 180°.
Therefore we have the equation:
5x - 5 + 6x + 31 = 180 <em>combine like terms</em>
(5x + 6x) + (-5 + 31) = 180
11x + 26 = 180 <em>subtract 26 from both sides</em>
11x = 154 <em>divide both sides by 11</em>
x = 14
The angles (5x - 5)° and z° are vertical angles.
Vertical angles are congruent.
Therefore we have the equation:
z = 5x - 5 <em>put x = 14 to the equation</em>
z = 5(14) - 5
z = 70 - 5
z = 65
Answer:
Look at the proof down
Step-by-step explanation:
The given is;
→ ∠1 and ∠2 form a linear pair
→ ∠1 ≅ ∠3
We want to prove;
→ ∠2 and ∠3 are supplementary
<em>We will write the proof in like a table</em>
1. ∠1 and ∠2 formed a linear pair ⇒ 1. Given
2. m∠1 + m∠2 = 180° ⇒ 2. Sum of angles on a straight line
3. ∠1 and ∠2 are supplementary angles ⇒ 3. Supplementary angles add up to 180°
4. ∠1 ≅ ∠3 ⇒ 4. Given
5. m∠2 + m∠3 = 180° ⇒ 5. Substitution method
6. ∠3 is a supplement of ∠2 ⇒ 6. Supplement of equal angles
7. ∠2 and ∠3 are supplementary ⇒ 7. Proved
The product of 5 and 2/3 is 5.6666
So the first thing you want to do when faced with two fractions with different denominators (when subtracting or adding) is to make the denominators the same. So for this equation they would turn out to be p+10/16=15/16 (because 16 is the lowest common denominator, 8 times two) so then you want to subtract 10/16 from 15/16 to isolate the variable (p) which would get:
p=5/16
This is the final answer because it cannot be simplified.
Hope this helps!
Answer:
- (a) no
- (b) yes
- (c) no
- (d) no
Step-by-step explanation:
"Of the order x^2" means the dominant behavior matches that of x^2 as x gets large. For polynomial functions, the dominant behavior is that of the highest-degree term.
For other functions, the dominant behavior will typically be governed in some other way. Here, the rate of growth of the x·log(x) function is determined by log(x), which has decreasing slope as x increases.
Only answer selection B has a highest-degree term of x^2, so only that one exhibits O(x^2) behavior.
