Answer:
cyber-extortion
Explanation:
Ashley Baker has been the webmaster for Berryhill Finance only ten days when she received an e-mail that threatened to shut down Berryhill's website unless Ashley wired payment to an overseas account. Ashley was concerned that Berryhill Finance would suffer huge losses if its website went down, so she wired money to the appropriate account. The author of the e-mail successfully committed cyber-extortion.
the answer is True
there has to be a balance between security and the user experience
Answer:
Explanation:
1. Write a program that declares an array named alpha with 50 components of the type double. Initialize the array so that the first 25 components are equal to the square of the counter (or index) variable and the last 25 components are equal to three times the index variable.
double alpha[50];
for (int i=0;i<25;i++)
{
alpha[i]=i*i;
alpha[i+25]=(i+25)*3;
}
2. Output the array so that exactly ten elements per line are printed.
for (int i=0;i<50;i++)
{
cout<<i+1<<". "<<alpha[i]<<" ";
if (((i+1)%10)==0)
{
cout<<endl;
}
}
3. Run your program again, but this time change the code so that the array is filled with random numbers between 1 and 100.
double alpha[50];
for (int i=0;i<50;i++)
{
alpha[i]=rand()%101;
}
for (int i=0;i<50;i++)
{
cout<<i+1<<". "<<alpha[i]<<" ";
if (((i+1)%10)==0)
{
cout<<endl;
}
}
4. Write the code that computes and prints the average of elements of the array.
double alpha[50],temp=0;
for (int i=0;i<50;i++)
{
alpha[i]=rand()%101;
temp+=alpha[i];
}
cout<<"Average :"<<(temp/50);
5. Write the code that that prints out how many of the elements are EXACTLY equal to 100.
double alpha[50],temp=0;
for (int i=0;i<50;i++)
{
alpha[i]=rand()%101;
if(alpha[i]==100)
{
temp++;
}
}
cout<<"Elements Exacctly 100 :"<<temp;
Please note: If you put each of above code to the place below comment it will run perfectly after compiling
#include <iostream>
using namespace std;
int main()
{
// If you put each of above code here it will run perfectly after compiling
return 0;
}
Answer:
Yes
Explanation:
Depending on the ethernet standard used, the IEEE 802.3 is faster than the WIFI (IEEE 802.11ac).
The ethernet protocol on cabled networks are of different speed based on ethernet standard which ranges from 10 Mega-bits to 100 Giga-bits per second. This protocol is found in the physical layer of the OSI model.
The wifi 802.11ac also known as wifi 5 is a wireless connection medium in the physical layer of the OSI model. It has a range of aggregate speed capacity of 433 mega-bits per second to 6.77 giga-bits per second.
