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3 years ago

2 * 10^-4 - 1 * 10^-5 Show your work.

1 answer:

7 0

<span>2 * 10^-4 - 1 * 10^-5
= 10^-4 ( 2 - 1 * 10^-1)
= 10^-4 ( 2 - 0.1)
= 10^-4 (1.9)
= 1.9 * 10^-4

hope it helps</span>

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Hii please help i’ll give brainliest if you give a correct answer.

Alex73 [517]

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3 0

2 years ago

A tea that is 22% jasmine is blended with a tea that is 13% jasmine. How many pounds of the 22% jasmine tea are used to make 10l

tatiyna

Given

A tea that is 22% jasmine is blended with a tea that is 13% jasmine

Find out the how many pounds of the 22% jasmine tea are used to make 10lb of tea that is 19.3% jasmine.

To proof

Let us assume that the a tea that is 22% jasmine is blended = a

Let us assume that the a tea that is 13% jasmine is blended = b

Total amount of tea made = 10lb

the equation be

a + b = 10

as given

jasmine tea are used to make 10lb of tea that is 19.3% jasmine.

write 22% in the decimal form

$= \frac{22}{100}$

= 0.22

write 13% in the decimal form

$=\frac{13}{100}$

= 0.13

write 19.3% in the decimal form

$=\frac{19.3}{100}$

= 0.193

than the equation be

0.22a + 0.13b = 0.193 × 10

on simplify

22a + 13b = 193

two equation becomes

22a + 13b = 193 and a + b = 10

multiply a + b = 10 by 13 and subtracted from the 22a + 13b = 193

we get

22a - 13a + 13b -13b = 193 - 130

9a = 63

a = 7lb

put this value in the a + b = 10

we get

7 + b = 10

b = 3lb

Therefore the 22% jasmine tea are used to make 10lb of tea that is 19.3% jasmine is 7 lb .

Hence proved

4 0

3 years ago

Please help!! Will mark brainliest!!

Natali [406]

Answer:

Step-by-step explanation:

it adds by 8, and if y is 14, 22, etc, then 8 would be the y in y = etc.

and if it starts ith 14, it adds by 8

3 0

2 years ago

Learning Task 1: Translate each of the following problem. Write your an swer in your notebook. 1. The quotient of $2 and 2 8 2.

finlep [7]

Answer:

1. 78/5

2. 12

3. 25/8

4. 48/35

5. 21/2

6 0

2 years ago

A scientist has a container of 2% acid solution and a container of 5% acid solution. How many fluid ounces of each concentration

algol [13]

Let 'a' be the number of ounces of 2%-solution in the 25-ounce mixture

and 'b' be the number of ounces of 5%-solution in the 25-ounce mixture.

Since, fluid ounces of each concentration should be combined to make 25 fl oz.

So, a+b=25 (Equation 1)

And, a container of 2% acid solution and a container of 5% acid solution should be combined to make 25 fl oz of 3.2% acid solution.

So, a of 2% + b of 5% = 3.2% of 25

$(a \times \frac{2}{100})+(b \times \frac{5}{100})= 25 \times \frac{3.2}{100}$

$(0.02a)+(0.05b)= 0.8$

Multiplying the above equation by 100, we get

$2a+5b=80$ (Equation 2)

Substituting the value of a=25-b in equation 2, we get

$2(25-b)+5b=80$

$50-2b+5b=80$

$50+3b=80$

$3b=30$

$b=10$

Since, a=25-b

a= 25-10

a=15.

So, 15 fluid ounces of 2% solution combined with 10 ounces of the 5% solution to create a 25-ounce mixture at 3.2% concentration of acid.

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2 years ago