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AfilCa [17]
4 years ago
13

A road bike has a wheel diameter of 622 mm. What is the circumference of the wheel? Use 3.14 for Pi.

Mathematics
2 answers:
egoroff_w [7]4 years ago
4 0

Answer:

4th option: 1953.08 mm

Step-by-step explanation:

circumference of circle= \pi d

Thus, circumference of wheel

= 3.14(622) \\  = 1953.08mm

makkiz [27]4 years ago
3 0

Answer:

<em>D.</em>

Step-by-step explanation:

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I need your help guys !!!!!!!!
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\bold{\huge{\blue{\underline{ Solution}}}}

\bold{\underline{ We \: have \:given \: that, }}

  • <u>Distance </u><u>between </u><u>the </u><u>house </u><u>and </u><u>tower </u><u>is </u><u>3</u><u>5</u><u> </u><u>m</u>
  • <u>The </u><u>height </u><u>of </u><u>the </u><u>tower </u><u>is </u><u>6</u><u>0</u><u> </u><u>m </u>
  • <u>The </u><u>height </u><u>of </u><u>the </u><u>house </u><u>is </u><u>2</u><u>5</u><u> </u><u>m</u>

\bold{\underline{ Now}}

  • <u> </u><u>Height</u><u> </u><u>of </u><u>the </u><u>house </u><u>is</u><u> </u><u>2</u><u>5</u><u>m</u>

\bold{\underline{ So, }}

\sf{ CE = 25m }

<u>Therefore</u><u>, </u>

\sf{ AB = AD - CE }

\sf{ AB = 60 - 25  }

\sf{ AB = 35 m }

<u>Now</u><u>, </u><u> </u><u>In </u><u>Right </u><u>angled </u><u>ABC</u>

\bold{tan Φ =}{\bold{\frac{ AB}{BC}}}

\bold{tan Φ =}{\bold{\frac{ 35}{35}}}

\bold{ tan Φ = 1 }

\bold{ tan Φ = 45 °}

\sf{\red{Hence, \: The \:angle \:of \:depression\: is \:45°}}

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2 years ago
How do I solve this? (Geometry)
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Step-by-step explanation:

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hope it helps

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Answer:

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Remember the decimal <em>hundredths</em> rounding ruleset.

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View this array below to get a better image.

\left[\begin{array}{ccc}0.49(down)&0.50(up)&0.51(up)\end{array}\right]

So, for example, if you had 6.51, you would round that up to 7, and if you had 8.47, you would round that to 8

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irinina [24]

9801/99= 99


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