

- <u>Distance </u><u>between </u><u>the </u><u>house </u><u>and </u><u>tower </u><u>is </u><u>3</u><u>5</u><u> </u><u>m</u>
- <u>The </u><u>height </u><u>of </u><u>the </u><u>tower </u><u>is </u><u>6</u><u>0</u><u> </u><u>m </u>
- <u>The </u><u>height </u><u>of </u><u>the </u><u>house </u><u>is </u><u>2</u><u>5</u><u> </u><u>m</u>

- <u> </u><u>Height</u><u> </u><u>of </u><u>the </u><u>house </u><u>is</u><u> </u><u>2</u><u>5</u><u>m</u>


<u>Therefore</u><u>, </u>



<u>Now</u><u>, </u><u> </u><u>In </u><u>Right </u><u>angled </u><u>ABC</u>





Answer:
Step-by-step explanation:
(3×10×8)÷26400= 0.00909090909
hope it helps
Answer:
- 5
- 6
- 6
- 5
Remember the decimal <em>hundredths</em> rounding ruleset.
- If a decimal is below .50, round down.
- If a decimal is .50, round up.
- If a decimal is above .50, round up.
View this array below to get a better image.
![\left[\begin{array}{ccc}0.49(down)&0.50(up)&0.51(up)\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0.49%28down%29%260.50%28up%29%260.51%28up%29%5Cend%7Barray%7D%5Cright%5D)
So, for example, if you had 6.51, you would round that up to 7, and if you had 8.47, you would round that to 8