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Virty [35]
3 years ago
14

. Choose the correct means and standard deviations for the Sincere and Insincere conditions. Make sure to round to two decimal p

lacesA. The Rudely Disagrees condition has a mean of 3.82 and a standard deviation of 0.85 while the Politely Disagrees condition has a mean of 4.16 and standard deviation of 0.97.B. The Rudely Disagrees condition has a mean of 4.16 and a standard deviation of 0.97 while the Politely Disagrees condition has a mean of 3.82 and standard deviation of 0.85.C. The Rudely Disagrees condition has a mean of 4.16 and a standard deviation of 0.85 while the Politely Disagrees condition has a mean of 3.82 and standard deviation of 0.97.D. The Rudely Disagrees condition has a mean of 3.82 and a standard deviation of 0.97 while the Politely Disagrees condition has a mean of 4.16 and standard deviation of 0.85.E. The Disagrees condition has a mean of 4.16 and a standard deviation of 0.85 while the Agrees condition has a mean of 3.82 and standard deviation of 0.97.
Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
8 0

Answer:

C. The rudely disagrees condition has a mean of 4.16 and a standard deviation of 0.85 while the politely disagrees condition has a mean of 3.82 and standard deviation of 0.97

Step-by-step explanation:

The given data is  

                                          x`             Std. Dev      

R. disagrees                  4.16       0.854        

P. disagrees                 3.82       0.967        

From this data we see that the R. disagrees has a mean of 4.16 and standard deviation of 0.854

while

the P. disagrees has a mean of 3.82 and standard deviation of 0.967.

Same figures are given only in option C because

Rounding 0.854 gives 0.85

Rounding 0.967 gives 0.97

So only option C is the best choice.

C. The R. Disagrees condition has a mean of 4.16 and a standard deviation of 0.85 while the P. Disagrees condition has a mean of 3.82 and standard deviation of 0.97

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valentinak56 [21]

Answer:

Z-statistic = 1.4017 < 1.96 at 0.05 level of significance

Null hypothesis is accepted

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Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given first sample size (n₁ ) = 57

Of the 57 Teen Court individuals, 18 subsequently recidivated during the 18-month follow-up period

First sample proportion

                                   p^{-} _{1} = \frac{x_{1} }{n_{1} } = \frac{18}{57} =0.3157

Second sample proportion

                               p^{-} _{2} = \frac{x_{2} }{n_{2} } = \frac{11}{54} =0.2037

Null Hypothesis : p₁⁻ = p₂⁻

Alternative Hypothesis :  p₁⁻ ≠ p₂⁻

<u><em>Step(ii)</em></u>:-

Test statistic

         Z = \frac{p_{1} ^{-} -p^{-} _{2} }{\sqrt{PQ(\frac{1}{n_{1} } +\frac{1}{n_{2} } )} }

        where

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Level of significance ∝ =0.05

The tabulated value Z₀.₀₅ = 1.96

Z-statistic = 1.4017 < 1.96 at 0.05 level of significance

Null hypothesis is accepted

The data suggest that the true proportion of Teen Court individuals who recidivate during the specified follow-up period differs from the proportion of Department of Juvenile Services individuals

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