Answer:
The equation of the blue graph is g(x)=(x-3)^{2} +1g(x)=(x−3)
2
+1 . Below is the explanation
Step-by-step explanation:
Given:
The graph of f(x)=x^{2}x
2
To find:
The equation of the transformed graph g(x).
The red graph f(x) is moved right 3 units and up 1 unit to get g(x).
When graph is moved right 3 units , 3 should be subtracted with x.
When graph is moved up 1 unit, 1 is added at the end.
So, our g(x)=(x-3)^{2} +1(x−3)
2
+1
The equation of the blue graph is g(x)=(x-3)^{2} +1g(x)=(x−3)
2
+1
Answer:
1.4
Step-by-step explanation:
Answer:
a) 72.25sec
b) 6.25secs
c) after 10.5secs and 2 secs
Step-by-step explanation:
Given the height reached by the rocket expressed as;
s(t)= -4t^2 + 50t - 84
At maximum height, the velocity of the rocket is zero i.e ds/dt = 0
ds/dt = -8t + 50
0 = -8t + 50
8t = 50
t = 50/8
t = 6.25secs
Hence it will reach the maximum height after 6.25secs
To get the maximum height, you will substitute t - 6.25s into the given expression
s(t)= -4t^2 + 50t - 84
s(6.25) = -4(6.25)^2 + 50(6.25) - 84
s(6.25) = -156.25 + 312.5 - 84
s(6.25) = 72.25feet
Hence the maximum height reached by the rocket is 72.25feet
The rocket will reach the ground when s(t) = 0
Substitute into the expression
s(t)= -4t^2 + 50t - 84
0 = -4t^2 + 50t - 84
4t^2 - 50t + 84 = 0
2t^2 - 25t + 42 = 0
2t^2 - 4t - 21t + 42 = 0
2t(t-2)-21(t-2) = 0
(2t - 21) (t - 2) = 0
2t - 21 = 0 and t - 2 = 0
2t = 21 and t = 2
t = 10.5 and 2
Hence the time the rocket will reach the ground are after 10.5secs and 2 secs
765 divides by 5 = 153.
Hope that helped! :)
Answer:
The minutes wouldn't it be hours?
Step-by-step explanation:
