Answer:
The answer would be 11 1/3 ft sqared
Answer:
B
Step-by-step explanation:
First, we need to work out the total number of students who were being surveyed.
We know that half of the students has two pets. The rest of the students make up the other half. So, we have 3 students + 2 students + 8 students = 13 students that make half of the sample population
That means total number of students being surveyed is 13+13=26 students
Then we work out the probability
P(One pet) = 8/26 = 4/13
P(Two pets) = 1/2
P(Three pets) = 3/26
P( Four pets) = 2/26 = 1/13
The probability distribution is shown in the table below. Let

be the number of pets and

is the probability of owning the number of pets
Answer:
Fraction: 81/100
Decimal: 0.81
Percentage: 81%
Step-by-step explanation:
The question is complete but the diagram mentioned can be found in
brainly.com/question/12188410
First step is to find the area of the whole square and then the area of the part that was shaded.
From the diagram, there are 100 squares in the whole square. 81 of those squares are shaded.
Area of the whole square = 10 by 10
= 10×10 = 100unit²
Area of shaded region = (10 by 8) + 1
= 80+1 = 81unit²
shaded area expressed as a fraction = 81unit²/100unit²
= 81/100
Shaded area expressed as a decimal = 81/100
You take the number 81 and carry the point by two decimal place from the right
= 0.81
Shaded area expressed as a percent of the whole = (81/100) × 100
= (81×100)/100
= 81%