Given the following table that gives data from a linear function:
![\begin {tabular} {|c|c|c|c|} Temperature, $y = f(x)$ (^\circ C)&0&5&20 \\ [1ex] Temperature, $x$ (^\circ F)&32&41&68 \\ \end {tabular}](https://tex.z-dn.net/?f=%5Cbegin%20%7Btabular%7D%0A%7B%7Cc%7Cc%7Cc%7Cc%7C%7D%0ATemperature%2C%20%24y%20%3D%20f%28x%29%24%20%28%5E%5Ccirc%20C%29%260%265%2620%20%5C%5C%20%5B1ex%5D%0ATemperature%2C%20%24x%24%20%28%5E%5Ccirc%20F%29%2632%2641%2668%20%5C%5C%20%0A%5Cend%20%7Btabular%7D)
The formular for the function can be obtained by choosing two points from the table and using the formular for the equation of a straight line.
Recall that the equation of a straight line is given by

Using the points (32, 0) and (41, 5), we have:
Answer:
the area of the shape is 7.14
Step-by-step explanation:
First, find the area of the square:
2 in x 2 in = 4 in
then to find the area of the semi- circles add them together to make a circle
To find the area of the circle, use:
pi x radius^2
Since the diameter is 2 divide the diameter by 2 to get radius
3.14 x 1^2 = 3.14
The circle is 3.14 plus 4 ( the square ) = 7.14
Answer:
the averege is 2.34
duh
Step-by-step explanation:
Answer:
About 9% or 0.09
Step-by-step explanation: