Answer:
Transitive property of equality
Step-by-step explanation:
Let A be any non empty set and R is any subset of the Cartesian product A × A. Then, R is a relation on A.
The relation R is said to be a transitive relation if (a, b) ∈ R, (b, c) ∈ R, then (a, c) ∈ R.
It is given that ABC = DEF and DEF = XYZ, then ABC = XYZ.
This shows the transitive property of equality.
<span>y=−3x+2</span> is a linear equation in slope-intercept form with
slope <span>m=<span>(−3)</span></span>
(and y-intercept <span>=2</span>)
We want the equation of a line with slope <span>m=<span>(−3)</span></span> through the point <span>(<span>−2</span>,<span>−8</span>)</span>
Using the point-slope linear equation form:
<span><span>(y−<span>(−8)</span>)</span>=<span>(−3)</span><span>(x−<span>(−2)</span>)</span></span>
Simplifying
<span>y+8=−3x−6</span>
or, in standard form
<span>3x+y=−<span>14</span></span>
Answer:
About 14.14
Step-by-step explanation:
V = 4/3pi x r^3
To find the radius, divide the diameter by 2 (1.5)
Substitute 1.5 in place of r and solve the equation.
Answer:
The desired equation is y = (-8/3)x + 26/3.
Step-by-step explanation:
Moving from (1,6) to (4, -2) involves an increase of 3 in x and a decrease of 8 in y. Thus, the slope of the line thru these two points is m = rise / run = -8/3.
Using the slope-intercept form of the eq'n of a straight line and inserting the data given (slope = m = -8/3, x = 4, y = -2), we get:
y = mx + b => -2 = (-8/3)(4) + b, or -2 = -32/3 + b
Multiply all terms by 3 to clear out the fraction:
-6 = -32 + 3b.
Then 26 = 3b, and b = 26/3.
The desired equation is y = (-8/3)x + 26/3.