All categories

2 years ago

Yo can someone help me out

Mathematics

2 answers:

WARRIOR [948]2 years ago

3 0

Answer:

1/48 square miles.

Step-by-step explanation:

(1/12)*(3/12) = 3/144

simplify into 1/48

Mashutka [201]2 years ago

3 0

<h2>˜”*°•.˜”*°• Question •°*”˜.•°*”˜</h2>

<em>The space where a new school will be built in the shape of a rectangle that is 1/12 miles wide and 3/12 mile long. What is the area of the space where the school will be built in square miles?</em>

<h2>˜”*°•.˜”*°• Answer •°*”˜.•°*”˜</h2>

1/48 square miles

<h2 /><h2>˜”*°•.˜”*°• Explanation •°*”˜.•°*”˜</h2>

Since this question is asking us to find the area of the rectangle:

a = l(w)

$\frac{1}{12}(\frac{3}{12}) = \frac{1}{48}$

<h2 /><h2>˜”*°•.˜”*°• Conclusion •°*”˜.•°*”˜ </h2>

Therefore, I can conclude that the area of the rectangle is 1/48 square miles.

(I think this might be wrong.)

You might be interested in

Saul decides to use the IQR to measure the spread of the data. Saul calculates the IQR of the data set to be . Saul asks Jasmine

Amiraneli [1.4K]

The question is incomplete. The compete question is :

Saul decides to use the IQR to measure the spread of data. Saul calculates the IQR of the data set to be 27. Saul asks Jasmine to check his work. Saul copies the data in numerical order from least to greatest for Jasmine. 25, 30, 50, 50, 50, 50, 56, n, 250. What is the value of n that will make the IQR of the data set equal to 27?

Solution :

The inter quartile range is being measured as : 3rd quartile - 1st quartile

The 1st quartile = 25% mark

The 3rd quartile = 75% mark

The data set as given in the question is :

25, 30, 50, 50, 50, 50, 56, n, 250

Therefore, the total number of the sample = 9

And the median is = 50

The median separates the given data sets into two equal halves-- that is the upper half and the lower half.

Let the middle of a lower half is the 1st quartile be $Q_1$

And the middle of a 2nd half is the 3rd quartile be $Q_3$

∴ $Q_1=\frac{30+50}{2}$

$=40$

$Q_3=\frac{56+n}{2}$

Now for the IQR of the data set to be equal to $27$ ,

$\frac{56+n}{2}-40=27$

$\frac{56+n}{2}=27+40$

$\frac{56+n}{2}=67$

$56 +n=134$

$n=134-56$

$n=78$

4 0

2 years ago

Math experts ONCE AGAIN :)<br> giving brainly!!

Paladinen [302]

Answer:

A) $49

Step-by-step explanation:

There are two ways to solve this problem. You could either calculate the net change by adding up the values in the table and then adding that to the initial amount, or you could individually add every change in price to the initial amount. I'm going to go with the first way, as I find it to be quicker, but both methods work equally well.

We know that the stock was worth $52 on Monday morning. From the table, the net (or overall) change in the stock over the course of the week is:

-2 + 1 + 3 - 1 - 4 = -3

Therefore, the stock's price decreased by $3 over the week, and because the stock's original price was $52, we know it is now worth 52 - 3 = $49. Hope this helps!

6 0

3 years ago

A speed limit of 100 kilometers per hour is approximately equal to 62mph. write an equation relating kilometers per hour to mile

aleksandr82 [10.1K]

Answer:

Step-by-step explanation:

IT DOES it

4 0

2 years ago

Birth weights at a local hospital have a Normal distribution with a mean of 110 oz and a standard deviation of 15 oz. The propor

OLga [1]

Answer:

The proportion of infants with birth weights between 125 oz and 140 oz is 0.1359 = 13.59%.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 110, \sigma = 0.15$