For questions 1-3
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( a + b )( a² - ab + b² )
Let us distribute ( a + b )
a ( a² ) + a ( - ab ) + a ( b² ) + b ( a² ) + b ( - ab ) + b ( b² )
a³ - a²b + ab² + a²b - ab² + b³
We can simplify further:
- a²b + a²b = 0
ab² - ab² = 0
a³ + b³
You can see in the picture I have attached that this is the 7th formula
( a + b )( a² - ab + b² )
Let us distribute ( a + b )
a ( a² ) + a ( - ab ) + a ( b² ) + b ( a² ) + b ( - ab ) + b ( b² )
a³ - a²b + ab² + a²b - ab² + b³
We can simplify further:
- a²b + a²b = 0
ab² - ab² = 0
a³ + b³
You can see in the picture I have attached that this is the 7th formula
Write the function as
f(x) = x² + 6x - 4
Note that
x² + 6x = (x + 3)² - 9
Therefore
f(x) = (x 3)² - 9 - 4
= (x + 3)² - 13
The vertex is at (-3, -13)., and the curve opens upward.
The axis of symmetry is x = -3.
Answer:
The vertex of the function is (-3, 13).
The graph increases over the interval (-3, -∞)
f(x) = x² + 6x - 4
Note that
x² + 6x = (x + 3)² - 9
Therefore
f(x) = (x 3)² - 9 - 4
= (x + 3)² - 13
The vertex is at (-3, -13)., and the curve opens upward.
The axis of symmetry is x = -3.
Answer:
The vertex of the function is (-3, 13).
The graph increases over the interval (-3, -∞)