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AleksAgata [21]
3 years ago
12

For questions 1-3

Mathematics
2 answers:
umka2103 [35]3 years ago
6 0
1) A 2) C 3) D


These are the answers
Liula [17]3 years ago
5 0

Answer: Direct Variation Practice

A, D, B, A, C, D, A, C, B, A


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By October 19th, Gordon had read 35 pages. Starting on October 20th, he decides to read the same number of pages each day until
PilotLPTM [1.2K]
Gordon read a total of 35 pages, so if there is p pages read per day and 10 days you'd have something that looks like this: 35 = 10p.

8 0
2 years ago
Which of the following is a common characteristic of a binomial distribution?
Tanya [424]

Answer:

E. Each trial is independent

Step-by-step explanation:

I'm not completely sure why all binomial distribution trials are independent, but there are requirements for binomial distributions.

These requirements are:

- Each outcome is either a success (p) or a failure (Q)

- All trials are independent

- There are a fixed number of "n" trials

- The probability of success (p) is the same for each trial

I also just took the test and got this right.

6 0
2 years ago
What is the value of x in 2(5x) = 14?
Ray Of Light [21]

Answer:

x= 7/5

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A cylindrical tank has a radius of 15 ft. and a height of 45 ft. How many cubic feet of water can the tank hold?
vladimir1956 [14]
The formula to solve for this would be pi(r^2)xheight. Essentially what this formula does is it takes the are of the base (pi x r^2) and multiplies it by the height of the cylinder to find how many times the base can stack on itself until it reaches the top. This formula of base are times height works for all prisms with two bases. Here are the steps to solve:

1) plug in the values
- pi(15^2) x 45

2) solve for the base area of one of the circles
- pi(15^2)=225pi

3) multiply the base area by the height
- 225pi x 45 = 10,125pi

4) final answer: the tank can hold 10,125pi cubic feet of water
4 0
3 years ago
Raíz cuadrada de 864
marshall27 [118]

Raíz cuadrada de 864

Para resolver este problema debemos tomar en cuenta los datos que nos dan y la ecuación de una hipérbola. Comencemos con los datos:

The general equation of ellipse is given as, x2a2+y2b2=1 x 2 a 2 + y 2 b 2 = 1 , where, a is length of semi-major axis and b is length of semi-minor axis.

centro: (0,0)

focus : (0, -√28) , (0, √28)

eje conjugado = 2√3

por los focos podemos ver que la hipérbola se dirige hacia el eje y, por lo que debemos tomar la siguiente forma de la ecuación de la parábola:

de los focos podemos obtener que: √28

y del eje conjugado podemos saber que al dividir la longitud del eje conjugado dentro de 2 obtenemos b, así que:

b = √3

podemos utilizar la siguiente fórmula para obtener a:

si despejamos a en la ecuación obtenemos lo siguiente:

ahora podemos sustituir los valores:

a=5

así que media vez conozcamos a, podemos sustituir los datos en la ecuación de la hipérbola así que obtenemos lo siguiente:

si graficamos la hipérbola, queda como en el documento adjunto.

To learn more hipérbola

Visit : brainly.com/question/24223341

#SPJ9

8 0
1 year ago
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