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aleksklad [387]
2 years ago
10

LeAnn is purchasing.giftwrap for a box that measures 10 inches long, 6 inches wide, and 6 inches tall. Calculate the total area

of the box that will be covered in.giftwrap. Show all of your work for full credit.
Mathematics
2 answers:
tigry1 [53]2 years ago
6 0

Answer:

the answers is 312 in²

Step-by-step explanation:

hope this help

choli [55]2 years ago
3 0

Answer:

\boxed{312~in^2}

Step-by-step explanation:

(P) Long = 10 in

(L) Wide = 6 in

(T) Tall = 6 in

.

So, Total area is

= 2(P\times L + P \times T + L\times T)

= 2(10\times 6 + 10 \times 6 + 6\times 6)

= 2(60 + 60 + 36)

= 2(156)

= 312~in^2

.

Happy to help :)

You might be interested in
Which coordinate point represents the y -intercept of the equation 3x + 2y = 18
scoundrel [369]

Answer:

(-6,18)

Step-by-step explanation:

3x + 2y = 18

2y= -3x + 18

y=-3/2 x + 18

give x=0

y=-3/2 *0+18

y=18#

y=18

3x+2(18)=18

3x+36=18

3x=18-36

3x=-18

x=-18/3

x=-6

5 0
2 years ago
Can someone please help me with 49 and 50 please. I will give Brainliest Answer.
Makovka662 [10]

Answer: 49=b

50=d

Step-by-step explanation:

4 0
3 years ago
Solve for x.<br> (5x - 24)<br> (8x + 9)
Stella [2.4K]

Answer:

40x^{2} - 147x - 216

Step-by-step explanation:

(5x - 24) (8x + 9)

First start with multiplying 5x to 8x and 9

40x^{2} +45x

then multiply -24 by 8x and 9

        -192 x  -216

40x^{2} +45x

        -192 x  -216

+

________________

40x^{2} - 147x - 216

7 0
3 years ago
There are three exams in your linear algebra class, and you theorize that your score in each exam (out of 100) will be numerical
Romashka [77]

Answer:

a) 40 hours

b) 60 hours

C) 100 hours

Step-by-step explanation:

0.2a + 0.3b+0.5c = 76

Hence: 0.2* (0.2 λ) +0.3*(0.3 λ )+0.5*(0.5 λ ) = 76

0.38 λ =76

λ = 76/0.38 =200

Thus : 40, 60, 100

7 0
3 years ago
The equation (x-6)^2/16 + (y+7)^2/4 = 1 represents an ellipse. What are the vertices of the ellipse?
topjm [15]

Answer:

The correct option is C.

Step-by-step explanation:

The given equation is

\frac{(x-6)^2}{16}+\frac{(y+7)^2}{4}= 1

It can be rewritten as

\frac{(x-6)^2}{4^2}+\frac{(y+7)^2}{2^2}= 1         .....(1)

The standard form of an ellipse is

\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}= 1           ....(2)

Where (h,k) is center of the ellipse.

If a>b, then the vertices of the ellipse are (h\pm a, k).

From (1) and (2) we get

h=6,k=-7,a=4,b=2

Since a>b, therefore the vertices of the ellipse are

(h+a, k)=(6+4,-7)\Rightarrow (10,-7)

(h-a, k)=(6-4,-7)\Rightarrow (2,-7)

The vertices of the given ellipse are (10, –7) and (2, –7). Therefore the correct option is C.

5 0
2 years ago
Read 2 more answers
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