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tatuchka [14]
4 years ago
15

Can some one help please

Advanced Placement (AP)
2 answers:
liraira [26]4 years ago
7 0
Hope this helps but I think it’s 14
nika2105 [10]4 years ago
5 0
It’s just the max(60) minus the min(46) so it should be 14
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HEYY I NEED HELP WITH AN AP CALC ASSIGNMENT ASAP
Vladimir79 [104]

CALCULATOR PART

1. The area of R + S is unsigned, meaning you want to find

\displaystyle\int_a^b\left|f(x)-g(x)\right|\,\mathrm dx

where [a,b] is the interval between the leftmost and rightmost intersections of f and g.

First use your calculator to find these intersections:

\cos x=\dfrac{x+1}3\implies x\approx-3.64,x\approx-1.86,x\approx0.889

so that a=-3.64 and b=0.889. Now compute the integral using your calculator:

\displaystyle\int_a^b\left|f(x)-g(x)|\,\mathrm dx\approx1.662

2. The volume, using the washer method, is given by the integral

\displaystyle\pi\int_{-1.86}^{0.889}(|2-g(x)|^2-|2-f(x)|^2)\,\mathrm dx\approx12.078

3. A circle of radius r has area \pi r^2; a semicircle with the same radius thus has area \frac{\pi r^2}2. Each cross section of this solid is a semicircle whose diameter is the vertical distance between f(x) and g(x), or |f(x)-g(x)|. In terms of the diameter d=2r, the area of each semicircle would be \frac{\pi d^2}8. Then the volume of the solid is

\displaystyle\frac\pi8\int_{-3.64}^{-1.86}|f(x)-g(x)|^2\,\mathrm dx\approx0.0425

NON-CALCULATOR PART

4. The mean value theorem says that for a function F continuous on an interval [a,b] and differentiable on (a,b), there is some c\in(a,b) such that

F'(c)=\dfrac{F(b)-F(a)}{b-a}

If this F happens to be an antiderivative of f, then we end up with

f(c)=\displaystyle\frac1{b-a}\int_a^bf(x)\,\mathrm dx

\cos x is continuous and differentiable everywhere, so the MVT applies. We have F'(x)=f(x)=\cos x, so the MVT tells us there is some c\in[0,\pi such that

\cos c=\dfrac{\sin\pi-\sin0}{\pi-0}=0

That is, the average value of f(x) on [0,\pi] is 0. The MVT says there is some c in the interval such that the function takes on the average value itself; this happens for c=\frac\pi2.

5. This question seems to be incomplete...

5 0
4 years ago
Music//
Sliva [168]
B because it was the best answer
6 0
3 years ago
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Jenny and Sam have been married for 15 years and have three children. Jenny and Sam respect each other, respect each other's rol
Verdich [7]

\green{\underline{{\boxed{\bf{QUESTION: }}}}}

Jenny and Sam have been married for 15 years and have three children. Jenny and Sam respect each other, respect each other's roles as parents, and have a deep affection for one another. What feeling is being described in Jenny and Sam's relationship?

\pink{\underline{{\boxed{\bf{OPTIONS:}}}}}

A) joy ❌

B) altruism ❌

C) attraction ❌

D) passionate love ❌

E) Companionate love✔️

\pink{\underline{{\boxed{\bf{ANSWER:}}}}}

Jenny & Sam have <u>c</u><u>ompa</u><u>n</u><u>i</u><u>o</u><u>nate love</u> cause they both have deep affection for one another. Companionate Love is Seen mainly in Couples only.

➪ Passionate love is seen mainly in the people who are in relation but haven't married. This love can also be seen in married couples if they have such strong love feeling towards each other.

6 0
3 years ago
Read 2 more answers
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