A right rectangular prism has a length of 8 ft, width of 8 1/4 ft, and height of 4 1/2 ft. What is the volume of the prism?

Mathematics

2 answers:

Dahasolnce [82]3 years ago

8 0

<u>Answer:</u>

297 cubic feet

<u>Step-by-step explanation:</u>

We are given that a right rectangular prism has a length of 8 ft, width of 8 1/4 ft, and height of 4 1/2 ft.

We are to find the volume of this prism.

We know the formula of volume of a rectangular prism is given by: $w \times h \times l$

where $w$ is the width, $h$ is the height and $l$ is the length of the prism.

So substituting the given values in the formula:

Volume of prism = $8\frac{1}{4} \times 4\frac{1}{2} \times 8 =$ 297 cubic feet

umka2103 [35]3 years ago

6 0

Answer:

Volume = 297 ft³

Step-by-step explanation:

We have given the length , height and width of the rectangular prism.

length = 8 ft , width = 8 1/4 ft and height = 4 1/2 ft

We have to find the volume of prism.

The formula to find the volume of prism is :

Volume = length × height × width

Putting given values in formula, we have

Volume = 8 × 4 1/2 × 8 1/4

Volume = 8 × 9/2 × 33/4

Volume = 8 × 4.5 × 8.25

Volume = 297 ft³ which is the answer.

You might be interested in

Use the distributive property to express 40 in a different form.

Artemon [7]

Answer:

5(4 + 4)

Step-by-step explanation:

5(4 + 4)

20 + 20

Hope this helps!

4 0

3 years ago

According to a poll, 83% of California adults (418 out of 506 surveyed) feel that education is one of the top issues facing Cali

SpyIntel [72]

Answer:

A point estimate for the true population proportion is $\hat{p} = 0.83$ and the 90% confidence interval is (0.8025, 0.8575)

Step-by-step explanation:

We have a large sample of people of size n = 506. Let X be the random variable that represents the number of adults who feel that education is one of the top issues facing California. We are interested in the unknown true proportion p of adults who feel that education is one of the top issues facing California. A point estimate for the true population proportion is given by $\hat{p}$ = X/n = 418/506 = 0.83, the standard deviation is given by $\sigma_{\hat{p}} = \sqrt{p(1-p)/n}\approx\sqrt{\hat{p}(1-\hat{p})/n} = \sqrt{(0.83)(0.17)/506} = 0.0167$ . Therefore, the 90% confidence interval for the true population proportion is $\hat{p}\pm z_{0.1/2}\sqrt{\hat{p}(1-\hat{p})/n}$ , i.e., $0.83\pm z_{0.05}0.0167$ , i.e., $0.83\pm (1.6448)(0.0167)$ , (0.8025, 0.8575).