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3 years ago

Please help !!!!! Explain to me and need answer quick

Mathematics

1 answer:

schepotkina [342]3 years ago

4 0

Answer:

We can see that the denominators of both the numbers is not same

So in order to make it same for the both numbers, we will multiply the second number by 2/2 ,(which is basically 1 so it won't affect our calculations)

$\frac{11}{2^2 * 5^2}$ - $\frac{2}{2^2 * 5^2}$

So we will just subtract the numbers now

$\frac{9}{2^2 * 5^2}$ <em>This is the answer </em>

<em>Kindly mark Brainly, Thanks</em>

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Cuanto da (9+4m)² cuadrado de binomio ayudaaaaa

Korolek [52]

Answer:

16m^2 + 72m + 81

Step-by-step explanation:

you expand it, by (9+4m)(9+4m), using distributive property you get

81 + 36m + 36m + 16m^2, simplifying you get the answer

8 0

1 year ago

I NEED HELP PLEASE! PLEASE PLEASE! I NEED A ANSWER FAST! PLEAZ!

denpristay [2]

C a rotation of 90deg

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3 years ago

Newton’s law of cooling states that dx/dt= −k(x − A) where x is the temperature, t is time, A is the ambient temperature, and k

Vadim26 [7]

Answer:

(a) The solution to the differential equation is x = A_0Coswt + Ce^(-kx)

(b) The initial condition t > 0 will not make much of a difference.

Step-by-step explanation:

Given the differential equation

dx/dt= −k(x − A); t > 0, A = A_0Coswt

(a) To solve the differential equation, first separate the variables.

dx/(x - A) = -kdt

Integrating both sides, we have

ln(x - A) = -kt + c

x - A = Ce^(-kt) (Where C = ce^(-kt))

x = A + Ce^(-kx)

Now, we put A = A_0Coswt

x = A_0Coswt + Ce^(-kx) (Where C is constant.)

And we have the solution.

(b) Since temperature t ≠ 0, the initial condition t > 0 will not make much of a difference because, Cos(wt) = Cos(-wt).

It is not any different from when t < 0.

7 0

3 years ago

Which term describes the fraction that has a variable or a variable expression

Lilit [14]

A term that describes the fraction that has a variable or valuable expression proper factor

3 0

3 years ago

A manufacturer of matches randomly and independently puts 23 matches in each box of matches produced. The company knows that one

d1i1m1o1n [39]

Answer:

0.9855 or 98.55%.

Step-by-step explanation:

The probability of each individual match being flawed is p = 0.008. The probability that a matchbox will have one or fewer matches with a flaw is the same as the probability of a matchbox having exactly one or exactly zero matches with a flaw:

$P(X\leq 1)=P(X=0)+P(X=1)\\P(X\leq 1)=(1-p)^{23}+23*(1-p)^{23-1}*p\\P(X\leq 1)=(1-0.008)^{23}+23*(1-0.008)^{23-1}*0.008\\P(X\leq 1)=0.8313+0.1542\\P(X\leq 1)=0.9855$

The probability that a matchbox will have one or fewer matches with a flaw is 0.9855 or 98.55%.

8 0

3 years ago