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katovenus [111]
4 years ago
12

What is the chemical name for vinegar

Physics
1 answer:
Law Incorporation [45]4 years ago
7 0
For vinegar it's Acetic Acid
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A rifle with a weight of 40 N fires a 5.5-g bullet with a speed of 220 m/s.(a) Find the recoil speed of the rifle.
liubo4ka [24]

Answer:

0.2695/s

Explanation:

Using the formula for calculating impulse

Impulse = m(v-u) = Ft

M is the mass

v is the final velocity.

u is the initial velocity

F is the force

t is the time

Get the time;

t = m(v-u)/F

t = 0.0055(220)/40

t = 0.0275s

Get the speed of the rifle

v = u+gt.

v = 0+9.8(0.0275).

v = 0.2695m/s

Hence the speed of the rifle is 0.2695m/s

3 0
3 years ago
What are the names of the four hemispheres of the earth
xenn [34]

Explanation:

Northern, Southern, Eastern, and Western.

6 0
3 years ago
A Ping-Pong ball moving East at a speed of 4 m/s collides with a stationary bowling ball. The Ping-Pong ball bounces back to the
In-s [12.5K]

Answer:

They experience the same magnitude impulse

Explanation:

We have a ping-pong ball colliding with a stationary bowling ball. According to the law of conservation of momentum, we have that the total momentum before and after the collision must be conserved:

p_i = p_f\\p_p + p_b = p'_p+p'_b

where

p_p is the initial momentum of the ping-poll ball

p_b is the initial momentum of the bowling ball (which is zero, since the ball is stationary)

p'_p is the final momentum of the ping-poll ball

p'_f is the final momentum of the bowling ball

We can re-arrange the equation as follows

p_p - p'_p = p_b'-p_b

or

-\Delta p_p = \Delta p_b

which means

|\Delta p_p | = |\Delta p_b| (1)

so the magnitude of the change in momentum of the ping-pong ball is equal to the magnitude of the change in momentum of the bowling ball.

However, we also know that the magnitude of the impulse on an object is equal to the change of momentum of the object:

I=\Delta p (2)

Therefore, (1)+(2) tells us that the ping-pong ball and the bowling ball experiences the same magnitude impulse:

|I_p| = |I_b|

4 0
4 years ago
in a hydraulic garage the small piston has a radius of 5 cm and the large piston has radius of 15 cm what force must be applied
viktelen [127]

The force applied to small piston = 2.2 x 10³ N

<h3>Further explanation</h3>

Given

a radius of 5 cm and 15 cm

weight 20000 N

Required

Force applied

Solution

Pascal Law :

F₁/A₁=F₂/A₂

A₁ = π.5²

A₂ = π.15²

F₁/ π.5² cm² = 20000/π.15² cm²

F₁ = 2222.22 N⇒2.2 x 10³ N

5 0
3 years ago
Rubbing your hands together warms them by converting work into thermal energy. If a woman rubs her hands back and forth for a to
KATRIN_1 [288]

Answer:

0.178 °C

Explanation:

Given:

The frictional force, F = 48 N

Number of rubs, n = 18

Distance covered per rub, d = 7.16 cm = 0.0716 m

Total distance covered in 18 rubs, D = 0.0716 × 18 = 1.288 m

mass of the tissues warmed, m = 0.1 kg

Now,

Work done, W = Force × Displacement

W = 48 × 1.288 = 61.8624 J

Now,

Work done is the change in heat

W = ΔQ = 61.8624 J

also,

ΔQ = mCΔT

where, C is the specific heat

for human tissue, C = 3470 J/kg°C

thus,

61.8624 J = 0.1 × 3470 × ΔT

or

ΔT = 0.178 °C

Hence, the change in temperature is 0.178 °C

6 0
4 years ago
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