Which form of energy is used in a wind-up toy robot?

Physics

2 answers:

Elan Coil [88]3 years ago

3 0

Answer:

D. MECHANICAL ENERGY

SANA MAKA TULONG

Sindrei [870]3 years ago

3 0

Answer:

the answer is D

Explanation:

because I know it is D

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(a) The skater covers a distance of S=50 m in a time of t=12.1 s, so its average speed is the ratio between the distance covered and the time taken:
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$v_i = 4 m/s$
while the final speed is
$v_f = 5.3 m/s$
and the time taken to accelerate to this velocity is t=2 s, so the acceleration of the skater is given by
$a= \frac{v_f - v_i}{t}= \frac{5.3 m/s-4.0 m/s}{2.0 s}=0.65 m/s^2$

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while the final speed is
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since she comes to a stop. The distance covered is S=8 m, so we can use the following relationship to find the acceleration of the skater:
$2aS=v_f^2 -v_i^2$
from which we find
$a= \frac{-v_i^2}{2S}= \frac{-(13.0m/s)^2}{2 \cdot 8.0 m}=-10.6 m/s^2$
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Explanation: