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steposvetlana [31]
4 years ago
8

-1/3(n+15)=-2, what is n

Mathematics
1 answer:
OlgaM077 [116]4 years ago
3 0
<span>-1/3(n+15)=-2
Use distributive property
-1/3n - 5=-2
Add 5 to both sides
-1/3n=3
Divide -1/3 on both sides
Final Answer: n=-9</span>
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Answer:

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Geometry - Will give 5 stars + Thanks!
Fynjy0 [20]

Answer:

<h2>x = 3 and y = 4</h2>

Step-by-step explanation:

We know:

The diagonals in a parallelogram divide by halves.

Therefore KG = UG and DG = CG.

We have

KG = 5y - 8, UG = 3y, DG = 4x - 7, CG = x + 2

Substitute:

5y - 8 = 3y          <em>add 8 to both sides</em>

5y = 3y + 8      <em>subtract 3y from both sides</em>

2y = 8      <em>divide both sides by 2</em>

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---------------

4x - 7 = x + 2           <em>add 7 to both sides</em>

4x = x + 9            <em>subtract x from both sides</em>

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4 years ago
Which is more 8 cups or 1 quart
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6<br><br><br> math geniuses help please!!<br><br><br> math
damaskus [11]

Answer:

A

Step-by-step explanation:

Begin with Euler's formula. I am assuming youre aware of this if youre taking complex algebra? You can prove Euler's formula by doing a Maclaurin expansion of cosine, sine, and e^x. Euler's formula states that:

e^{ix}=cos(x)+isin(x)

We can put the first complex number in exponetial form by noticing the input is 2pi/3. The second complex number has an input of pi/3. Therefore:

z_1=8e^{i(2\pi /3)}

z_2=0.5e^{i(\pi /3)}

Then:

\frac{z_1}{z_2} =\frac{8e^{i(2\pi /3)}}{0.5e^{i(\pi /3)}}

Simplify the coefficients to get:

\frac{z_1}{z_2} =\frac{16e^{i(2\pi /3)}}{e^{i(\pi /3)}}

When you divide exponentials, you subtract the exponents. Therefore:

\frac{z_1}{z_2} =16e^{i(2\pi /3)-i(\pi /3)}=16e^{i(\pi /3)

Put it back into trigonemtric form using Euler's formula:

16e^{i(\pi /3)}=16cos(\pi /3)+i16sin(\pi /3)

Cosine of pi/3 is 0.5, and sine of pi/3 is square root of 3 over 2. We have:

16e^{i(\pi /3)}=16cos(\pi /3)+i16sin(\pi /3)=16*0.5+16*\frac{\sqrt{3} }{2} *i=8+8\sqrt{3} i

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Answer:

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Step-by-step explanation:

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