15% = .15
add 1.00 to include the original amount
9 *(1+0.15) = 10.35
so $10.35
(6,1)&(5,4)
(7,-3)&(4,-8)
(-8,0)&(1,5)
Basically, you are to find the line that passes through 2 points.
Equation: y2-y1=m(x2-x1)
• x1: 6, x2: 5, y1: 1, y2: 4
(4-1)/(5-6)=m
m=3/-1
m=-3
Hence, m= -3x10^0
• x1: 7, x2: 4, y1: -3, y2: -8
(-8--3)/(4-7)=m
m=(-8+3)/-3
m=-5/-3
m=5/3
m=1.66666667
Hence, m=1.6667x10^0
• x1: -8, x2: 1, y1: 0, y2: 5
(5-0)/(1--8)=m
m=5/(1+8)
m=5/9
m=0.55555556
Hence, m=5.56x10^-1
Hope this helps!
Answer: The slope of the line = 4.
Step-by-step explanation:
We know that ,
Slope of a line passes through and =
Here , the line passes through points (2,18) and (8,42).
Then the slope of the given line =
Hence, the slope of the line = 4.
Step-by-step explanation:
2 (yellow) / 3.5 (blue)
that means, out of 2+3.5 = 5.5 units 2 are yellow, and 3.5 units are blue.
now in a 3 / 4.5 ratio we have 3+4.5 = 7.5 units, where 3 units are yellow and 4.5 units are blue.
let's bring both ratios to the same denominator (bottom part of the fraction).
if we multiply 3.5 by 2 we get 7. and multiplying 4.5 by 2 gives us 9.
and the smallest common multiple of 7 and 9 is 63.
so, let's bring both fraction to .../63.
3.5 × 2 × 9 = 63
so, the ratio is
2×2×9/63 = 36/63
and
4.5 × 2 × 7 = 63
so, that ratio is then
3 × 2 × 7 / 63 = 42/63
now we can see clearly that the first ratio
2/3.5 = 36/63 has fewer units of yellow in the mix than the second ratio
3/4.5 = 42/63.
so, the second mixture is more yellow.
Answer:
C. -3 must be a root of the polynomial 2·x² + 9·x + 9
Step-by-step explanation:
Given that the remainder when (2·x² + 9·x + 9) is divided by (x + 3) equals zero, then (x + 3) is a factor of 2·x² + 9·x + 9 and -3 is a root of the polynomial
Explaining by using the long division of the polynomial is presented as follows;
<u>2·x + 3</u>
(2·x² + 9·x + 9)/(x + 3)
<u>- (2·x² + 6·x)</u>
3·x + 9
-(3·x + 9)
0
Therefore, (2·x + 3) × (x + 3) = 2·x² + 9·x + 9
The solution of the 2·x² + 9·x + 9 = 0 gives the root of the polynomial
The root is given by, 2·x² + 9·x + 9 = (2·x + 3) × (x + 3) = 0
Therefore, the roots are;
2·x = -3 or x = -3/2 and x = -3
Therefore;
-3 must be a root of the polynomial 2·x² + 9·x + 9.