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4 years ago

in this diagram, AB and CD are Parallel. Angle ABC measure 35 and Angle BAC measure 115, what is the angle of ACE.

Mathematics

1 answer:

ZanzabumX [31]4 years ago

5 0

Answer:

180°

Step-by-step explanation:

I think this is the answer

because the line is straight from the point ACE

see

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(-8,3)(-3,-4.5) what is zero of g?

Crank

Answer:

the daimeter of the heart of the heart of the heart

4 0

3 years ago

A function is given. g(x) = 6 x ; x = 1, x = a. determine the net change between the given values of the variable.

Pavlova-9 [17]

The net change between the given values of the variable is 6a - 6

<h3>How to determine the net change between the given values of the variable?</h3>

The given parameters are

g(x) = 6x

Where

x = 1 and x =a

Calculate g(1) and g(a)

So, we have

g(1) = 6 * 1

g(1) = 6

g(a) = 6 * a

g(a) = 6a

The net change between the given values of the variable is

Change = g(a) - g(1)

So, we have

Change = 6a - 6

Hence, the net change between the given values of the variable is 6a - 6

Read more about functions at:

brainly.com/question/1415456

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2 years ago

Chang knows one side of a triangle is 13 cm. Which set of two sides is possible for the lengths of the other two sides of this t

Lelechka [254]

8cm and 8cm.

Espero que esta respuesta te ayude.

4 0

3 years ago

Which is the value of this expression when p=-2 and q=-1?

saul85 [17]

Answer:

D. 4

Step-by-step explanation:

$[(p^2) (q^{-3}) ]^{-2}.[(p)^{-3}(q)^5] ^{-2}\\\\=[(p^2) (q^{-3}) \times(p)^{-3}(q)^5 ]^{-2}\\\\=[(p^{2}) \times(p)^{-3} \times (q^{-3}) \times(q)^5 ]^{-2}\\\\=[(p^{2-3}) \times (q^{5-3}) ]^{-2}\\\\=[(p^{-1}) \times (q^{2}) ]^{-2}\\\\=(p^{-1\times (-2)}) \times (q^{2\times (-2) }) \\\\=p^{2}\times q^{-4} \\\\= \frac{p^2}{q^4}\\\\= \frac{(-2)^2}{(-1)^4}\\\\= \frac{4}{1}\\\\= 4$

8 0

3 years ago

Please help. <br> Find the value of h in the triangle.

dybincka [34]

1/2×12m×18.2m=109.2m2
109.2m2÷21.8m÷1/2=10m(nearest whole number)
h=10m

3 0

3 years ago

Read 2 more answers