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Step2247 [10]
3 years ago
9

Name a pair of vertical angles, a straight angle, and two acute angles other than

Mathematics
1 answer:
malfutka [58]3 years ago
3 0

Step-by-step explanation:

While there are no examples available, there is the room to understand each angle type you listed, vertical angles are angles that are opposite from each other, and they are congruent (they have the same angle in degrees) now, imagine that for vertical angles, they are in an X top and bottom are equal, and the two sides are equal. For a straight angle, that is usually two angles that are right angles (90 degrees) back to back, meaning when you add 90 and 90 degrees together, you get a straight line or a 180 degree angle. An example of an acute angle is any angle less than 90 degrees, that is a real number, so imagine 25, 40, and 60 as all acute angles.

Hope this helps you identify them in your problem!

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Answer:

t=\frac{23-24}{\frac{5}{\sqrt{5}}}=-0.447    

p_v =P(t_{(4)}  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't reject the claim that the true mean is at least 24 mpg (null hypothesis) at 1% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=23 represent the sample mean

s=5 represent the sample standard deviation for the sample  

n=5 sample size  

\mu_o =24 represent the value that we want to test

\alpha=0.1 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is lower than 24 (rejecting the claim proposed), the system of hypothesis would be:

Null hypothesis:\mu \geq 24  

Alternative hypothesis:\mu < 24  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{23-24}{\frac{5}{\sqrt{5}}}=-0.447    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=5-1=4  

Since is a one sided test the p value would be:  

p_v =P(t_{(4)}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't reject the claim that the true mean is at least 24 mpg at 1% of signficance.  

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