Question

A solid right pyramid has a regular hexagonal base with an area of 7.4 units2. The pyramid has a height of 6 units. What is the volume of the pyramid

Answer 1

Answer:

$14.8\text{ Units}^3$

Step-by-step explanation:

We have been given that the base area of a right pyramid with hexagonal base is 7.4 square units. The pyramid has a height of 6 units.

To find the volume of the given pyramid we will use formula:

$\text{Volume of hexagonal pyramid}=\text{ Base area}\times \frac{\text{Height}}{3}$

$\text{Volume of hexagonal pyramid}=7.4\text{ Units}^2\times \frac{\text{6 units}}{3}$

$\text{Volume of hexagonal pyramid}=7.4\text{ Units}^2\times \text{2 units}$

$\text{Volume of hexagonal pyramid}=14.8\text{ Units}^3$

Therefore, the volume of given hexagonal pyramid is 14.8 cubic units.

Answer 2

Answer:

14.8 cubic units

Step-by-step explanation:

The volume of the right pyramid can be calculated using formula

$V_{pyramid}=\dfrac{1}{3}\cdot A_{base}\cdot height.$

You are given

$A_{base}=7.4\ un^2.\\ \\height=6\ un.$

Then

$V_{pyramid}=\dfrac{1}{3}\cdot 7.4\cdot 6=2\cdot 7.4=14.8\ un^3.$