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3 years ago

9

A solid right pyramid has a regular hexagonal base with an area of 7.4 units2. The pyramid has a height of 6 units. What is the

volume of the pyramid

2 answers:

vodomira [7]3 years ago

8 0

Answer:

$14.8\text{ Units}^3$

Step-by-step explanation:

We have been given that the base area of a right pyramid with hexagonal base is 7.4 square units. The pyramid has a height of 6 units.

To find the volume of the given pyramid we will use formula:

$\text{Volume of hexagonal pyramid}=\text{ Base area}\times \frac{\text{Height}}{3}$

$\text{Volume of hexagonal pyramid}=7.4\text{ Units}^2\times \frac{\text{6 units}}{3}$

$\text{Volume of hexagonal pyramid}=7.4\text{ Units}^2\times \text{2 units}$

$\text{Volume of hexagonal pyramid}=14.8\text{ Units}^3$

Therefore, the volume of given hexagonal pyramid is 14.8 cubic units.

liberstina [14]3 years ago

5 0

Answer:

14.8 cubic units

Step-by-step explanation:

The volume of the right pyramid can be calculated using formula

$V_{pyramid}=\dfrac{1}{3}\cdot A_{base}\cdot height.$

You are given

$A_{base}=7.4\ un^2.\\ \\height=6\ un.$

Then

$V_{pyramid}=\dfrac{1}{3}\cdot 7.4\cdot 6=2\cdot 7.4=14.8\ un^3.$

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A recipe calls for 32 fluid ounces of heavy cream. How many 1-pint containers of heavy cream are needed to make the recipe? show

Cloud [144]

1 pint is 16 fluid ounces
32 divided by 16 equals 2
Answer: 2 pint containers of heavy cream is needed to make the recipe

8 0

3 years ago

What is an equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 ?

Natali5045456 [20]

Answer:

The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is

$6x+y=-5$

Step-by-step explanation:

Given:

Let,

point A( x₁ , y₁) ≡ ( -2 , 7)

To Find:

Equation of Line that passes through the point (-2,7) and is perpendicular to the line x-6y=42=?

Solution:

$x-6y=42$ ..................Given

which can be written as

$y=mx+c$

Where m is the slope of the line

∴ $y=\dfrac{x}{6}-7$

On Comparing we get

$Slope = m = \dfrac{1}{6}$

The Required line is Perpendicular to the above line.

So,

Product of slopes = - 1

$m\times m_{1}=-1\\Substituting\ m\\ \dfrac{1}{6} m_{1}=-1\\\\m_{1}=-6$

Slope of the required line is -6

Equation of a line passing through a points A( x₁ , y₁) and having slope m is given by the formula,

i.e equation in point - slope form

$(y-y_{1})=m(x-x_{1})$

Now on substituting the slope and point A( x₁ , y₁) ≡ ( -2, 7) and slope = -6 we get

$(y-7)=-6(x--2)=-6(x+2)=-6x-12\\\\\therefore 6x+y=-5.......is\ the required\ equation\ of\ the\ line$

The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is

$6x+y=-5$

3 0

3 years ago

2. Create a linear function that has a rate of change of 3 and a solution at (6, 12).

Ksivusya [100]

Answer:

$y = 3x - 6$

Step-by-step explanation:

A linear function has the following format:

$y = ax + b$

In which a is the slope(rate of change) and b is the y-intercept, that is, the value of y when x = 0.

Rate of change of 3

This means that $a = 3$

So

$y = 3x + b$

A solution at (6, 12).

This means that when x = 6, y = 12. So

$y = 3x + b$

$12 = 3*6 + b$

$b = -6$

The linear function is:

$y = 3x - 6$

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4 years ago

The probability of rolling a sum of 5 from a pair of dice is. What are your odds in favor of rolling a sum of 5?

tamaranim1 [39]

Answer:

1/9

Step-by-step explanation:

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3 years ago

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Lena [83]

Answer:

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3 years ago