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Vilka [71]
3 years ago
9

A solid right pyramid has a regular hexagonal base with an area of 7.4 units2. The pyramid has a height of 6 units. What is the

volume of the pyramid
Mathematics
2 answers:
vodomira [7]3 years ago
8 0

Answer:

14.8\text{ Units}^3

Step-by-step explanation:

We have been given that the base area of a right pyramid with hexagonal base is 7.4 square units. The pyramid has a height of 6 units.

To find the volume of the given pyramid we will use formula:

\text{Volume of hexagonal pyramid}=\text{ Base area}\times \frac{\text{Height}}{3}

\text{Volume of hexagonal pyramid}=7.4\text{ Units}^2\times \frac{\text{6 units}}{3}

\text{Volume of hexagonal pyramid}=7.4\text{ Units}^2\times \text{2 units}

\text{Volume of hexagonal pyramid}=14.8\text{ Units}^3

Therefore, the volume of given hexagonal pyramid is 14.8 cubic units.

liberstina [14]3 years ago
5 0

Answer:

14.8 cubic units

Step-by-step explanation:

The volume of the right pyramid can be calculated using formula

V_{pyramid}=\dfrac{1}{3}\cdot A_{base}\cdot height.

You are given

A_{base}=7.4\ un^2.\\ \\height=6\ un.

Then

V_{pyramid}=\dfrac{1}{3}\cdot 7.4\cdot 6=2\cdot 7.4=14.8\ un^3.


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<h3>I'll teach you how to solve 8*(8+4-10)</h3>

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lara31 [8.8K]

Answer:

x = 8

Step-by-step explanation:

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2 years ago
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Answer:

<em>The perimeter is 72 units and the area is 149 square units.</em>

Step-by-step explanation:

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Using the distance formula.........

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<u>Formula for the Area of triangle</u>,  A= \frac{1}{2}(base\times height)

So, the area of the \triangle SBA will be:  \frac{1}{2}(\sqrt{1130}\times 8.89)= 149.42... \approx 149 square units.   <em>(Rounded to the nearest unit)</em>

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