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Evgesh-ka [11]
3 years ago
10

HELP PLZZZZZ Solve for Y

Mathematics
2 answers:
11111nata11111 [884]3 years ago
6 0

Answer:

y = 29

Step-by-step explanation:

i have no explanation because  it would take a wile to find the informathion again i have the question before tho

kakasveta [241]3 years ago
5 0
20^2+21^2=Y^2
400+441=Y^2
Y^2=841
Y=29
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The perimeter of a rectangular park is 500 feet. The length of the park is 100 feet longer than the width. Find the length of th
lord [1]

Answer:

The length of the park is 175 feet

Step-by-step explanation:

Let us solve the question

∵ The perimeter of a rectangular park is 500 feet

∵ The formula of the perimeter of the rectangle is P = 2(L + W)

∵ L is the length and W is the width

→ Equate the rule of the perimeter by 500

∴ 2(L + W) = 500

→ Divide both sides by 2

∴ L + W = 250 ⇒ (1)

∵ The length of the park is 100 feet longer than the width

→ That means L is W plus 100

∴ L = W + 100 ⇒ (2)

→ Substitute L in (1) by (2)

∵ W + 100 + W = 250

→ Add the like terms

∵ (W + W) + 100 = 250

∴ 2W + 100 = 250

→ Subtract 100 from both sides

∵ 2W + 100 - 100 = 250 - 100

∴ 2W = 150

→ Divide both sides by 2

∴ W = 75

→ Substitute the value of W in (2) to find L

∵ L = 75 + 100 = 175

∴ The length of the park is 175 feet

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