You can use photomath it will give you the exact steps
The wording is unorthodox, but I believe the answer is D.
The probability that you can get N heads in a row would be:
Let <span>p</span> be the probability of flipping a heads. Let <span>x</span> be number of flips needed to achieve <span>h </span>consecutive heads. The solution is <span><span>E(x) = (<span><span>1−<span>p^h) / (</span></span><span><span>p^h</span>(1−p))</span></span></span></span>
This expression may be derived as follows. The probability of being successful immediately is <span><span>p^r.</span></span> However, one might get a tails immediately. In that case, the number of flips needed is <span><span>1+E(x) </span></span>(one flip has been used and we are back to the original position). We might get a heads and then a tails. In this case two flips have been used and we are back to the original position. Continue this up to <span><span>h−1</span></span> heads followed by a tails in which case <span>h</span> flips have been used and we are back to the original position.
Answer:
16
Step-by-step explanation:
Okey dokey my dude, here's the deal. All you have to do to answer this is use order of operations (parentheses exponents multiplication division addition subtraction).
8÷2(<u>2+2</u>)=?
//parenthesis first
8÷2(4)
//Ok here's where people will mess up. They just look at the problem and assume that you should multiply the 2 and (4) first because the 4 is in parenthesis. That's understandable, but wrong. What the equation should really look like is 8÷2·4. So you should do 8÷2 first.
<u>8÷2</u>·4=?
4·4=?
<u>16=16</u>
25 is A
26 is B because (8x2)+(11x3)=49
