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Katyanochek1 [597]
2 years ago
15

1. A translation of function f is f1(x) = b(x – h). It is equivalent to

Mathematics
1 answer:
svetoff [14.1K]2 years ago
7 0
4 will be the correct answer to your question
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If equation for the straight line passing through the point (-2; 3 ) and (- 3; 2)
galina1969 [7]
The equation for that line is y=x+5
4 0
3 years ago
20+30-10+40=80<br>true or false​
Katena32 [7]

Answer:

true

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Easton wants to put a variety of donuts in a display case. The case is large enough to hold 100 donuts. Complete the table below
shutvik [7]

The amounts for each donut are given as follows:

  • Strawberry: 15.
  • Chocolate: 45.
  • Sprinkle: 40.

<h3>How to obtain the amounts?</h3>

The amounts for each donut are found applying the proportion, multiplying the decimal equivalent of each percentage by the total number of donuts.

From the problem, the total number of donuts is given as follows:

100 donuts.

The percentages of each type of donuts are given as follows:

  • Strawberry: 15%.
  • Chocolate: 45%.
  • Sprinkle: 40%.

The decimal equivalent of each percentage is given as follows:

  • Strawberry: 0.15.
  • Chocolate: 0.45.
  • Sprinkle: 0.4.

Hence the amounts are given as follows:

  • Strawberry: 15, as 0.15 x 100 = 15.
  • Chocolate: 45, as 0.45 x 100 = 45.
  • Sprinkle: 40, as 0.4 x 100 = 40.

More can be learned about proportions at brainly.com/question/24372153

#SPJ1

3 0
1 year ago
What is the completely factored form of 12xy-9x-8y+6?
PilotLPTM [1.2K]
Rearrange slightly...

12xy-8y-9x+6 now factor 1st and 2nd pair of terms

4y(3x-2)-3(3x-2)

(4y-3)(3x-2)
8 0
3 years ago
Read 2 more answers
Solving Exponential and Logarithmic Equations In Exercise, solve for x.<br> In 2x - In(3x - 1) = 0
LenKa [72]

Answer:

\frac{-1}{3x^2-x}

Step-by-step explanation:

  1. If f(x) is in th form of f(x)=g(x)-h(x) then f'(x)=g'(x) - h'(x)
  2. When f(x)=z(g(x)) then f'(x)= z'(g(x))g'(x) (called as chain rule)

<u>using these information</u>:

g(x)=ln2x then g'(x)=\frac{(2x)'}{2x} =\frac{2}{2x}=\frac{1}{x}

h(x)=In(3x - 1) then h'(x)=\frac{(3x-1)'}{3x-1} =\frac{3}{3x-1}f'(x)=g'(x) - h'(x) =[tex]\frac{1}{x} - \frac{3}{3x-1} =\frac{-1}{3x^2-x}

7 0
3 years ago
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