3 years ago

Find an expression for the nth term of the arithmetic sequence. 2, 8, 14, 20, 26, . . .

Mathematics

1 answer:

IceJOKER [234]3 years ago

8 0

Answer:

Step-by-step explanation:

Math boi

You might be interested in

What measurement is equal to 6 kilometers

salantis [7]

Answer:

where is the options? or is any given.

Step-by-step explanation:

4 0

3 years ago

PLEASE HELP ME OUT HERE!!!!<br> THIS IS DUE TODAY!!!!!

dolphi86 [110]

Answer:

I'm pretty sure the answer is b

5 0

3 years ago

Read 2 more answers

A water tank has a square base of area 5 square meters. Initially the tank contains 70 cubic meters. Water leaves the tank, star

ANEK [815]

Answer:

$9.2\ \text{m}$

Step-by-step explanation:

$b$ = Surface area of base = 5 square meters

Volume of water in tank = 70 cubic meters

The rate at which the volume is reducing is

$\dfrac{dV}{dt}=2+4t\\\Rightarrow dV=2+4tdt$

Integrating from $t=0$ to $t=3$

$V=\int^3_0(2+4t)dt\\\Rightarrow V=2t+2t^2|_0^3\\\Rightarrow V=2\times 3+2\times 3^2-0\\\Rightarrow V=24$

Volume of water remaining in the tank is $70-24=46\ \text{m}^3$

Suface area of base $\times$ depth = Volume

$5\times d=46\\\Rightarrow d=\dfrac{46}{5}\\\Rightarrow d=9.2\ \text{m}$

The depth of the water remaining in the tank is $9.2\ \text{m}$ .

3 0

3 years ago

Rationalize the denominator of the fraction and enter the new denominator below.<br><br>8/2-√12

Studentka2010 [4]

$\frac{8}{2-\sqrt{12}}=\frac{8}{2-\sqrt{4\cdot3}}=\frac{8}{2-2\sqrt3}=\frac{8}{2(1-\sqrt3)}=\frac{4}{1-\sqrt3}\\\\\frac{4}{1-\sqrt3}\cdot\frac{1+\sqrt3}{1+\sqrt3}=\frac{4(1+\sqrt3)}{1^2-(\sqrt3)^2}=\frac{4(1+\sqrt3)}{1-3}=\frac{4(1+\sqrt3)}{-2}=-2(1+\sqrt3)}\\\\=-2-2\sqrt3$

$if\ \frac{8}{2}-\sqrt{12}=4-\sqrt{4\cdot3}=4-2\sqrt3$

8 0

3 years ago

Read 2 more answers

Jack bought a shirt for $14 because it was discounted 30%. what is the regular price?

Andru [333]

All you have to do is 14*.30 which equals to $4.20

8 0

3 years ago