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3 years ago

Given: circle k(O) m∠R = (12x+1)mFP = (11x+7) mPQ= 60Find: mFP

Mathematics

1 answer:

zhannawk [14.2K]3 years ago

5 0

Answer:

62°

Step-by-step explanation:

The angle R inscribes the arc FQ, so using the property of inscribed angles in a circle, we have that:

m∠R = mFQ / 2

The arc FQ is the sum of the arcs FP and PQ, so we have:

mFQ = mFP + mPQ = 11x + 7 + 60 = 11x + 67

Now, with the first equation, we have:

12x + 1 = (11x + 67) / 2

24x + 2 = 11x + 67

13x = 65

x = 5°

So we have that mFP = 11x + 7 = 55 + 7 = 62°

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In triangle abc, m of acb = 90, cd is perpendicular to ab , m of acd is 60. and bd is 5 cm. find ad

weeeeeb [17]

Let us draw a picture to make the things more clear.

Attached is the image.

We have been given that

$\angle acd = 60 ^{\circ}$

Therefore, we have

$\angle dcb =90- 60= 30 ^{\circ}$

Now, in triangle bcd, we have

$\tan30 = \frac{5}{cd}\\
\\
\frac{1}{\sqrt 3}=\frac{5}{cd}\\
\\
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\\
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\\
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\\
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