All categories

2 years ago

Given: circle k(O) m∠R = (12x+1)mFP = (11x+7) mPQ= 60Find: mFP

Mathematics

1 answer:

zhannawk [14.2K]2 years ago

5 0

Answer:

62°

Step-by-step explanation:

The angle R inscribes the arc FQ, so using the property of inscribed angles in a circle, we have that:

m∠R = mFQ / 2

The arc FQ is the sum of the arcs FP and PQ, so we have:

mFQ = mFP + mPQ = 11x + 7 + 60 = 11x + 67

Now, with the first equation, we have:

12x + 1 = (11x + 67) / 2

24x + 2 = 11x + 67

13x = 65

x = 5°

So we have that mFP = 11x + 7 = 55 + 7 = 62°

You might be interested in

Will mark brainlest how to multipy it

Lesechka [4]

Answer:

$\displaystyle x = 2 \sqrt{3}$

Step-by-step explanation:

we would like to solve the following equation:

$\displaystyle \sqrt{3} = \frac{6}{x}$

in order to do so do cross multiplication:

$\displaystyle x \sqrt{3} = 6$

divide both sides by √3:

$\displaystyle x = \frac{6}{ \sqrt{3}}$

since we ended up with a square root on the denominator so we can consider rationalising the denominator to do so multiply both numerator and denominator by √3 which yields:

$\displaystyle x = \frac{6}{ \sqrt{3}} \times \frac{ \sqrt{3} }{ \sqrt{ 3} }$

simplify multiplication:

$\displaystyle x = \frac{6 \sqrt{3} }{ 3}$

reduce fraction:

$\displaystyle x = 2 \sqrt{3}$

and we are done!

6 0

3 years ago

A circle is centered at the point (-3,2) and passes through the point (1,5). What is the radius of the circle?

Akimi4 [234]

Answer:

Step-by-step explanation:

The radius is a distance on a circle from the center to a point on the circle.

We have both of these points describe here in this definition. Using the distance formula will give us the radius.

$\sqrt{(x \text{ difference })^2+(y \text{ difference})^2$

The difference between 1 and -3 is 1-(-3)=4.

The difference between 5 and 2 is 5-2=3.

$\sqrt{4^2+3^2}$

$\sqrt{16+9}$

$\sqrt{25}$

$5$

8 0

3 years ago

Which graph represents a function that is decreasing at a nonconstant rate?

Tasya [4]

Answer: C

since the line isn't straight, the slope/function is decreasing but not at a constant rate

3 0

3 years ago

Find the area of the following figure below

icang [17]

140
explanation: ......

6 0

3 years ago

Cos (90-theta) • cosec90-theta) =tano. How?

denis-greek [22]

Answer:

______________________________________________________

TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-

For any right angled triangle with one angle α ,

$\cos (90 - \alpha ) = \sin \alpha$ or $\sin(90 - \alpha ) = \cos\alpha$

$cosec \: (90 - \alpha ) = \sec\alpha$ or $\sec(90 - \alpha ) = cosec\:\alpha$

SOME GENERAL TRIGNOMETRIC FORMULAS :-

$\sin \alpha = \frac{1}{cosec \: \alpha }$ or $cosec \: \alpha = \frac{1}{\sin \alpha }$

$\cos \alpha = \frac{1}{\sec \alpha }$ or $\sec \alpha = \frac{1}{\cos \alpha }$

______________________________________________________

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

$\cos (90 - \alpha ) \times cosec(90 - \alpha )$

$=> sin\alpha \times \sec\alpha$

$=> \sin\alpha \times \frac{1}{\cos\alpha }$

$=> \frac{\sin\alpha }{\cos\alpha }$

$=> \tan\alpha$ = R.H.S.

∴ L.H.S. = R.H.S. (Proved)

3 0

3 years ago