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Nataliya [291]
3 years ago
8

Need help please on geometry

Mathematics
2 answers:
zimovet [89]3 years ago
4 0
To solve this we are going to use the formula for the area of a circle: A= \frac{1}{4} \pi d^2
where
A is the area of the circle 
d is the diameter of the circle 

We know from our problem that the area of our circle is 10 inches long, so d=10in. Lets replace that value in our formula to find A:
A=\frac{1}{4} \pi (10in)^2
A=78.54in^2

We can conclude that the correct answer is: 78.54 square inches, or in centimeters: 506.7 square cm.
mojhsa [17]3 years ago
4 0
The area of a circle is:

A = pi*r^2

given:
d = 10inches
r = 10/2 inches = 5inches

so the are of the given circle is 

A = pi*5^2 = 25pi in.sq

Convert inches to cm;

25pi in.sq ( 127cm / 50 inches )^2 = 161.29pi cm.sq
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Bus stop Restaurant sell 3/4 as many cheeseburgers as they do with hamburgers on any given day. If there are a total of 42 burge
schepotkina [342]

Answer:

24cb 18 hb

Step-by-step explanation:

Let's call C the number of cheese burger sold and H the number of hamburgers.

As the cheeseburger sold are 3/4 of hamburgers, we can represent with the following equation:

C= (3/4)H (equation 1)

The total of burgers sold are the total of cheeseburger plus the total of hamburgers, and the sum 42. The equation representing it is:

C + H = 42

Replacing C by its value of eq. 1:

(3/4)H + H = 42

(3/4)H + (4/4)H = 42

(7/4) H = 42

Dividing both sides by (7/4)

H = 42/(7/4)

H= 42*(4/7)

H= (42/7)*4

H= 6*4

H=24

Then, C is:

C=(3/4)H

C=(3/4)*24

C= 3*24/4

C=72/4

C=18

We can verify it summing C+H

C+H=24+18=42 verified!

6 0
3 years ago
A box has dimensions of 17 inches long 1.3 feet wide and 8 inches high what is the volume of the box the formula of the volumes
nataly862011 [7]
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4 years ago
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garik1379 [7]

Hence, the function increases at a constant multiplicative rate..

<h2>What is a function?</h2>

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We know,

the answer is (B) the function increases at a constant multiplicative rate.

to learn more about functions: brainly.com/question/25638609

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