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matrenka [14]
2 years ago
15

Ok here’s another question

Mathematics
2 answers:
slega [8]2 years ago
6 0

Answer:

20 necklaces

Step-by-step explanation:

If Elizebeth is starting off w/10 necklaces we can find on the graph that $10 buys an additional 10 necklaces. Now knowing that information we can add 10 necklaces to our original necklaces and get 20 necklaces. We can also find that our unit rate of change is 10 dollars : 10 necklaces or 1 dollar : 1 necklace. Knowing this can help us solve future problems like how many necklaces can Elizebeth get for x dollars.

Marizza181 [45]2 years ago
5 0
The answer is 20 necklaces
Explanation:
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What is 3.1 as a mixed fraction in simplest form
zmey [24]
The word form of 3.1 is three and one tenth. "Three and one tenth" could also be a mixed number, so all we do is get the mixed number "three and one tenth":
3 \frac{1}{10}
3 0
3 years ago
Read 2 more answers
Solve the inequality <br> 21≥t+10
olchik [2.2K]

The answer is t ≤ 11.

  1. Subtract 10 from each side.
  • 21 - 10 ≥ t + 10 - 10
  • t ≤ 11

6 0
1 year ago
A car insurance company has determined that 66​% of all drivers were involved in a car accident last year. Among the 1010 driver
jenyasd209 [6]

Answer: Our required probability is 0.618.

Step-by-step explanation:

Since we have given that

Probability of all drivers were involved in a car accident last year = 66%

Number of drivers = 10

Number of drivers involved in a car accident = 3

So, probability of drivers involved in car accident is given by

\dfrac{3}{10}\\\\=0.3

Probability of getting 3 or more who were involved in a car accident is given by

P(X≥3)=1-P(X=0)-P(X=1)-P(X=2)

Here,

P(X=0)=^{10}C_0(0.7)^{10}=0.028\\\\P(X=1)=^{10}C_1(0.7)^9(0.3)=0.121\\\\P(X=2)=^{10}C_2(0.7)^8(0.3)^2=0.233

So, our equation becomes

P(X≥3)=1-P(X=0)-P(X=1)-P(X=2)

P(X\geq 3)=1-0.028-0.121-0.233=0.618

Hence, our required probability is 0.618.

4 0
3 years ago
In 1984 a locally-owned car company sold 2,743 cars. In 2003, the car sales rose to 4,069. What was the average rate of change f
tatiyna

Answer:

70 cars  per year.

Step-by-step explanation:

Given:

In 1984 a locally-owned car company sold 2,743 cars.

In 2003, the car sales rose to 4,069.

Question asked:

What was the average rate of change for the total number of cars sold?

Solution:

In 2003 number of cars sold = 4069

In 1984 number of cars sold = 2743

Change in the number of car sold = 4069 - 2743

                                                         = 1326

Now, time interval between 2003 and 1984 = 19

The\ average\ rate\ of\ change=\frac{Change\ in\ the\ number\ of\ car\ sold}{Time \ interval}

                                             =\frac{1326}{19} \\=69.789\\\\=70\ cars\ per\ year\  (approx)

Thus, the average rate of change for the total number of cars sold is 70 cars  per year.

7 0
3 years ago
Explain how an estimate helps you place the decimal point when multiplying 3.9 × 5.3
4vir4ik [10]
An estimate helps you place the decimal point when multiplying because if you find out how many decimals there are and once you are done doing you estimated multiplication you put two decimal points after that.


Hope I helped some what and didn't make you confused.

4 0
3 years ago
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