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r-ruslan [8.4K]
3 years ago
8

What is the value of A when we rewrite 15x as A^x/6

Mathematics
2 answers:
Elis [28]3 years ago
8 0

Answer:

B

Step-by-step explanation:

I did the work :)

marusya05 [52]3 years ago
3 0

Answer:

b

Step-by-step explanation:

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What is the equation of a line that contains the points (2,-2) and (0, -2)?
balu736 [363]

Answer:

y = - 2

Step-by-step explanation:

The equation of a horizontal line parallel to the x- axis is

y = c

where c is the value of the y- coordinates the line passes through.

The points (2, - 2) and (0, - 2) have the same y- coordinate and therefore lie on a horizontal line with equation

y = - 2

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3 years ago
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An orange has 30 calories more than a peach
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Answer:

O = p + 30

13p = 7o

O is (x+30)

O = 1+30 ....31

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Use the distributive property to write the expression as a product<br> 10+70x
grigory [225]

Answer:

10(1+7x)

Step-by-step explanation:

Just factored out the 10.

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Vin invested $6800 in an account with continuously compounded interest with a 7.3% interest rate. After 6 years, how much money
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3 years ago
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Four lawn sprinkler heads are fed by a 1.9-cm-diameter pipe. The water comes out of the heads at an angle of 35° above the horiz
klemol [59]

Answer:

Step-by-step explanation:

Given:

Angle, θ = 35°

Vertical distance, Δx = 6 m

Diameter, d = 1.9 cm

= 0.019 m

A.

When the water leaves the sprinkler, it does so at a projectile motion.

Therefore,

Using equation of motion,

(t × Vox) = 2Vo²(sin θ × cos θ)/g

= Δx = 2Vo²(sin 35 × cos 35)/g

Vo² = (6 × 9.8)/(2 × sin 35 × cos 35)

= 62.57

Vo = 7.91 m/s

B.

Area of sprinkler, As = πD²/4

Diameter, D = 3 × 10^-3 m

As = π × (3 × 10^-3)²/4

= 7.069 × 10^-6 m²

V_ = volume rate of the sprinkler

= area, As × velocity, Vo

= (7.069 × 10^-6) × 7.91

= 5.59 × 10^-5 m³/s

Remember,

1 m³ = 1000 liters

= 5.59 × 10^-5 m³/s × 1000 liters/1 m³

= 5.59 × 10^-2 liters/s

= 0.0559 liters/s.

For the 4 sprinklers,

The rate at which volume is flowing in the 4 sprinklers = 4 × 0.0559

= 0.224 liters/s

C.

Area of 1.9 cm pipe, Ap = πD²/4

= π × (0.019)²/4

= 2.84 × 10^-4 m²

Volumetric flowrate of the four sprinklers = 4 × 5.59 × 10^-5 m³/s

= 2.24 × 10^-4 m³/s

Velocity of the water, Vw = volumetric flowrate/area

= 2.24 × 10^-4/2.84 × 10^-4

= 0.787 m/s

7 0
3 years ago
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