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4 years ago

Need help on this question. Anything is appreciated:) (8th grade math)

Mathematics

1 answer:

satela [25.4K]4 years ago

7 0

Answer:

Step-by-step explanation:

Put 5 in frist box and literally any number other than 15 in the other

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Mixed number fraction 7 1/5+3 2/5

andrezito [222]

Answer: 10 3/5

Step-by-step explanation: 7+3 = 10

1+2=3

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4 years ago

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An exponential function has a maximum and a minimum value True or false?

Ymorist [56]

An expo fn, such as y = e^x, has neither max nor min. The graph of y = e^x begins in Quadrant II and ends in Quadrant I; it has no upper limit. As x becomes smaller and smaller, the graph approaches, but does not touch, the x-axis.

FALSE

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4 years ago

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Please Help ASAP AP calculus Due in 1 day!!! Marking Brainliest!!!

MaRussiya [10]

Answer:

(D) $\displaystyle \frac{12}{1 + ln8}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Functions
Function Notation

Calculus

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Integration

Integration Rule [Fundamental Theorem of Calculus 2]: $\displaystyle \frac{d}{dx}[\int\limits^x_a {f(t)} \, dt] = f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = \int\limits^{x^3}_1 {\frac{1}{1 + ln(t)}} \, dt$

Step 2: Differentiate

Chain Rule: $\displaystyle f'(x) = \frac{d}{dx} \bigg[ \int\limits^{x^3}_1 {\frac{1}{1 + ln(t)}} \, dt \bigg] \cdot \frac{d}{dx}[x^3]$
Integration Rule - Fundamental Theorem of Calculus 2: $\displaystyle f'(x) = \frac{1}{1 + ln(x^3)} \cdot \frac{d}{dx}[x^3]$
Basic Power Rule: $\displaystyle f'(x) = \frac{1}{1 + ln(x^3)} \cdot 3x^{3 - 1}$
Simplify: $\displaystyle f'(x) = \frac{3x^2}{1 + ln(x^3)}$

Step 3: Evaluate

Substitute in x [Derivative]: $\displaystyle f'(2) = \frac{3(2)^2}{1 + ln(2^3)}$
Exponents: $\displaystyle f'(2) = \frac{3(4)}{1 + ln(8)}$
Multiply: $\displaystyle f'(2) = \frac{12}{1 + ln(8)}$