Please help me. Thnx

When the car moves forward by 180cm , each wheel does one full turn . What is the diameter of the wheels to the nearest cm?

Sav [38]

Since 180cm is one full turn you divide it by pie which is 3.14

=180/3.14

=180/3 (Rounded down)

=60

3 0

3 years ago

Explain how to correctly find the missing side

kotegsom [21]

Pythagorean Theorem

a² + b² = c²

c = 13

a = 4

(Missing side) = b

4² + b² = 13²

16 + b² = 169

16 - 16

169 - 16 = 153

Square Root of 153 = 12.369

b = 12.369

The missing side is 12.369 (rounded to 12 as a whole number)

6 0

2 years ago

Read 2 more answers

Help me on this question

tatyana61 [14]

Answer:

The single transformation that maps shape A into shape B is 4 steps right and 3 steps down.

8 0

3 years ago

A ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is h-48t -16t^2.

Marat540 [252]

Answer:

36 feet.

Step-by-step explanation:

We have been given that a ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is $h(t)=-48t -16t^2$ . We are asked to find the maximum height of the ball.

We can see that our given equation is a downward opening parabola, so its maximum height will be the vertex of the parabola.

To find the maximum height of the ball, we need to find y-coordinate of vertex of parabola.

Let us find x-coordinate of parabola using formula $x=-\frac{b}{2a}$ .

$x=-\frac{-48}{2(-16)}$

$x=-\frac{48}{32}$

$x=-\frac{3}{2}$

So, the x-coordinate of the parabola is $-\frac{3}{2}$ . Now, we will substitute $x=-\frac{3}{2}$ in our given equation to find y-coordinate of parabola.

$h(t)=-48t -16t^2$

$h(-\frac{3}{2})=-48(-\frac{3}{2})-16(-\frac{3}{2})^2$

$h(-\frac{3}{2})=-24(-3)-16(\frac{9}{4})$

$h(-\frac{3}{2})=72-4*9$

$h(-\frac{3}{2})=72-36$

$h(-\frac{3}{2})=36$

Therefore, the maximum height of the ball is 36 feet.

3 0

3 years ago

The number of milligrams of a certain medicine a veterinarian gives to a dog varies directly with the weight of the dog. If the

Andre45 [30]

Answer:

Step-by-step explanation:

A direct variation equation is of the form

y = kx,

where, in words, it reads "y varies directly with x" or "y varies directly as x". In order to use this as a model, we have to have enough information to solve for k, the constant of variation. The constant of variation is kind of like the slope in a straight line. It rises or falls at a steady level; it is the rate of change.

We have that a vet gives a dose of three-fifths mg to a 30 pound dog. If the dose varies directly with the weight of the dog, then our equation is

d = kw and we need to find k in order to have the model for dosing the animals.

$\frac{3}{5} =k(30)$