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Arte-miy333 [17]
3 years ago
13

HELP ME ASAP 1. (-4/3)-(-3/2) 2 -3.9-8.9 3 2.9-(-9.4)

Mathematics
1 answer:
solmaris [256]3 years ago
3 0
Here is your first answer:

First find whats common which is 6:

-4×2=-8
3×2=6
-3×3=-9
2×3=6

Subtract -9 and -8
But use KCC which makes the equation...
-9+8=-1
-1/6

Here is your second answer:

First use KCC to Chang the equation into...

-3.9
-8.9

Then add:

9+9=18
=-1.28

Here is your third answer:

First change the equation (KCC):

2.9
9.4

9+4=13
3.9=12
=1.23

There are your answers:
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the answer is
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7 0
3 years ago
Solve for x, if. 3(x-8)-5=9(x+2)+1 the answer is 7.166 but i don't know how they got it
djverab [1.8K]
The answer and workings are in the document below. Please open it up in a new window to see it in full.

7 0
2 years ago
Read 2 more answers
Find the? inverse, if it? exists, for the given matrix.<br><br> [4 3]<br><br> [3 6]
True [87]

Answer:

Therefore, the inverse of given matrix is

=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}

Step-by-step explanation:

The inverse of a square matrix A is A^{-1} such that

A A^{-1}=I where I is the identity matrix.

Consider, A = \left[\begin{array}{ccc}4&3\\3&6\end{array}\right]

\mathrm{Matrix\:can\:only\:be\:inverted\:if\:it\:is\:non-singular,\:that\:is:}

\det \begin{pmatrix}4&3 \\3&6\end{pmatrix}\ne 0

\mathrm{Find\:2x2\:matrix\:inverse\:according\:to\:the\:formula}:\quad \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}^{-1}=\frac{1}{\det \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}}\begin{pmatrix}d\:&\:-b\:\\ -c\:&\:a\:\end{pmatrix}

=\frac{1}{\det \begin{pmatrix}4&3\\ 3&6\end{pmatrix}}\begin{pmatrix}6&-3\\ -3&4\end{pmatrix}

\mathrm{Find\:the\:matrix\:determinant\:according\:to\:formula}:\quad \det \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}\:=\:ad-bc

4\cdot \:6-3\cdot \:3=15

=\frac{1}{15}\begin{pmatrix}6&-3\\ -3&4\end{pmatrix}

=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}

Therefore, the inverse of given matrix is

=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}

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The last one is =z

hope this helps.

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