We are to select 2 people to sit in first row from 6.

This is a problem of Combinations. We are find permutation of 6 people taken 2 at a time. This can be represented as 6C2.

$6C2= \frac{6!}{4!*2!} \\ \\=15$

So, the answer is option B

7 0

2 years ago

Find the missing side lengths

sesenic [268]

Answer:

$\sin(45) = \frac{o}{h} \\ 0.7 = \frac{x}{18 \sqrt{2} } \\ 0.7 \times 18 \sqrt{2} = x \\ 0.7 \times 25.45 = x \\ 17.8 = x$

${x}^{2} + {y}^{2} =( 18 \sqrt{2} ) ^{2} \\ {17.8}^{2} + {y}^{2} = 648 \\ 316.84 + {y}^{2} = 648 \\ {y}^{2} = 648 - 316.84 \\ {y}^{2} = 331.16 \\ y = 18.19$

5 0

2 years ago

I need help to find the area

leonid [27]

Answer: multiply the two values to get the area

Step-by-step explanation:

Pls put me as brainliest

4 0

3 years ago

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