The Answer Is D -1 because five -1 against 6 -1 ends up to a positive 1
Answer:
22 games
Step-by-step explanation:
In order to find the minimum number of games that Enzo played we need to find the least common multiple of tickets where both Enzo and Beatrice are equal. To do this we simply find all the multiples of the number of games each could have played by the number of tickets per game until we find one in common.
5*1 = 5 11*1 = 11
5*2 = 10 11*2 = 22
5*3 = 15 11*3 = 33
5*4 = 20 11*4 = 44
5*5 = 25 11*5 = 55
... ...
... ...
... ...
5*22 = 110 11*10 = 110
Finally, we can see that the minimum amount of games that Enzo needs to play in order for both Enzo and Beatrice to have the same amount of tickets is 22 games.
Answer:
<h2>5/198</h2>
<em>Hope that helps! :)</em>
<em></em>
<em>-Aphrodite</em>
Step-by-step explanation:
Part of the value of sin(u) is cut off; I suspect it should be either sin(u) = -5/13 or sin(u) = -12/13, since (5, 12, 13) is a Pythagorean triple. I'll assume -5/13.
Expand the tan expression using the angle sum identities for sin and cos :
tan(u + v) = sin(u + v) / cos(u + v)
tan(u + v) = [sin(u) cos(v) + cos(u) sin(v)] / [cos(u) cos(v) - sin(u) sin(v)]
Since both u and v are in Quadrant III, we know that each of sin(u), cos(u), sin(v), and cos(v) are negative.
Recall that for all x,
cos²(x) + sin²(x) = 1
and it follows that
cos(u) = - √(1 - sin²(u)) = -12/13
sin(v) = - √(1 - cos²(v)) = -3/5
Then putting everything together, we have
tan(u + v)
= [(-5/13) • (-4/5) + (-12/13) • (-3/5)] / [(-12/13) • (-4/5) - (-5/13) • (-3/5)]
= 56/33
(or, if sin(u) = -12/13, then tan(u + v) = -63/16)
