Ask question

Ask question

All categories

3 years ago

8

Find an equation that models a hyperbolic lens with a = 12 inches and foci that are 26 inches apart. Assume that the center of t

he hyperbola is the origin and the transverse axis is vertical.

1 answer:

marta [7]3 years ago

8 0

The general form for a hyperbola with the center at the origin and a vertical transverse axis is:
y2/a2 - x2/b2 = 1

From the given:
a = 12

To get b, we use the given distance between the foci.Since it's 26,
c = 26/2 = 13

Using this defintion:
c2 = a2 + b2
b = sqrt(c2 - a2) = sqrt (13^2 - 12^2) = 5

The equation therefore is:
y2/13^2 - x2/5^2 = 1
or
y2/169 - x2/25 = 1

You might be interested in

What is the answer EXPLAIN HOW YOU GOT IT FOR BRAINLEST

Paul [167]

Let's first see which box and whisker plots have a range of 17. The range is maximum-minimum. ( the last dot minus the first dot). For A. 20 - 4 = 16, so it can't be A. For B. 36-2 = 34, so it can't be B. For C. 36 - 19 = 17, so it could be C. And for D. 17 - 2 = 15, so it can't be D. C. must be the correct answer, but let's check if the interquartile range is 5. The IQR ( interquartile range) is the 3rd Quartile - the 1st Quartile. 33- 28 = 5. So, C. is the correct answer! Hope this helped!

5 0

3 years ago

F(x) = x^2. what us g(x)?

Likurg_2 [28]

Answer:

Ues

Step-by-step explanation:

Ues papa math or demos and that should help

6 0

3 years ago

Sanya has a piece of land which is in the shape of a rhombus. She wants her one daughter and one son to work on the land and pro

Neporo4naja [7]

${\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}$

★ Sanya has a piece of land which is in the shape of a rhombus.

★ She wants her one daughter and one son to work on the land and produce different crops, for which she divides the land in two equal parts.

★ Perimeter of land = 400 m.

★ One of the diagonal = 160 m.

${\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}$

★ Area each of them [son and daughter] will get.

${\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}$

Let, ABCD be the rhombus shaped field and each side of the field be $x$

[ All sides of the rhombus are equal, therefore we will let the each side of the field be $x$ ]

Now,

• Perimeter = 400m

$\longrightarrow \tt AB+BC+CD+AD=400m$

$\longrightarrow \tt x + x + x + x=400$

$\longrightarrow \tt 4x=400$

$\longrightarrow \tt \: x = \dfrac{400}{4}$

$\longrightarrow \tt x= \red{100m}$

$\therefore$ Each side of the field = <u>100m</u><u>.</u>

Now, we have to find the area each [son and daughter] will get.

So, For $\triangle$ ABD,

Here,

• a = 100 [AB]

• b = 100 [AD]

• c = 160 [BD]

$\therefore \tt Simi \: perimeter \: [S] = \boxed{ \sf \dfrac{a + b + c}{2} }$

$\longrightarrow \tt S = \dfrac{100 + 100 + 160}{2}$

$\longrightarrow \tt S = \cancel{ \dfrac{360}{2}}$

$\longrightarrow \tt S = 180m$

Using <u>herons formula</u><u>,</u>

$\star \tt Area \: of \: \triangle = \boxed{\bf{{ \sqrt{s(s - a)(s - b)(s - c) } }}} \star$

where

• s is the simi perimeter = 180m

• a, b and c are sides of the triangle which are 100m, 100m and 160m respectively.

<u>Putt</u><u>ing</u><u> the</u><u> values</u><u>,</u>

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{180(180 - 100)(180 - 100)(180 - 160) }$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{180(80)(80)(20) }$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{180 \times 80 \times 80 \times 20 }$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{9 \times 20 \times 20 \times 80 \times 80}$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{ {3}^{2} \times {20}^{2} \times {80}^{2} }$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = 3 \times 20 \times 80$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \red{ 4800 \: {m}^{2} }$

Thus, area of $\triangle$ ABD = <u>4800 m²</u>

As both the triangles have same sides

So,

Area of $\triangle$ BCD = 4800 m²

<u>Therefore, area each of them [son and daughter] will get = 4800 m²</u>

${\large{\textsf{\textbf{\underline{\underline{Note :}}}}}}$

★ Figure in attachment.

${\underline{\rule{290pt}{2pt}}}$

7 0

1 year ago

Read 2 more answers

bazaltina [42]

Answer:gotta go sorry

Step-by-step explanation:

3 0

3 years ago

Which term describes a function in which the y-values form a geometric sequence

romanna [79]

The geometric sequence is a sequence in which the proceeding number is equal to the preceeding number multiplied by a ratio. The expression that represents this sequence is an = a1*r^(n-1) where r is the ratio and n is an integer. This type of formula is exponential

8 0

3 years ago