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3 years ago

13

Hi! Can you please help me? I am learning about like terms, and other things. I am kind of confused. Here is an example of what

I am doing in school. I am in pre algebra-
2(2z+5)=
2(2z+5)=
\,\,50
50

1 answer:

tigry1 [53]3 years ago

8 0

Your answer is 4z+10

Hope this helps

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What is the solution set to the inequality

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$(4x - 3)(2x - 1) \geqslant 0 \\ \Leftrightarrow \begin{cases}4x - 3 \geqslant 0 \\ 2x - 1 \geqslant 0\end{cases}\: \vee \:\begin{cases}4x - 3 \leqslant 0 \\2x - 1 \leqslant 0 \end{cases} \\ \Leftrightarrow \begin{cases}x \geqslant \frac{3}{4} \\ x \geqslant \frac{1}{2} \end{cases}\: \vee \:\begin{cases}x\leqslant \frac{3}{4} \\x \leqslant \frac{1}{2} \end{cases} \\ \Leftrightarrow x \geqslant \frac{3}{4} \: \vee \: x \leqslant \frac{1}{2} \\ \Rightarrow The\: third\: option$

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A home has a triangular backyard. The second angle of the triangle is 4degrees more than the first angle. The third angle is 8de

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3rd angle = X + 18

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If the pattern continues, how many stars will be in the Stage 15 figure?

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Suppose you solved a second-order equation by rewriting it as a system and found two scalar solutions: y = e^5x and z = e^2x. Th

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Answer:

The solutions are linearly independent because the Wronskian is not equal to 0 for all x.

The value of the Wronskian is $\bold{W=-3e^{7x}}$

Step-by-step explanation:

We can calculate the Wronskian using the fundamental solutions that we are provided and their corresponding the derivatives, since the Wroskian is defined as the following determinant.

$W = \left|\begin{array}{cc}y&z\\y'&z'\end{array}\right|$

Thus replacing the functions of the exercise we get:

$W = \left|\begin{array}{cc}e^{5x}&e^{2x}\\5e^{5x}&2e^{2x}\end{array}\right|$

Working with the determinant we get

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Thus we have found that the Wronskian is not 0, so the solutions are linearly independent.

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3 years ago

In the equation, 6(3x+5) -4x =35 , what are some of the steps that should be taken to solve for x? Select all that apply.

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You need to combine like terms and subtract 30. How you find the answer is you work the problem first 1. Distribute the 6 (18x+30)-4x=35 then 2. combine like terms 18x and -4x. (14x+30)=35 then 3. Subtract 30 from both sides (14x)=5

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