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3 years ago

13

Hi! Can you please help me? I am learning about like terms, and other things. I am kind of confused. Here is an example of what

I am doing in school. I am in pre algebra-
2(2z+5)=
2(2z+5)=
\,\,50
50

1 answer:

tigry1 [53]3 years ago

8 0

Your answer is 4z+10

Hope this helps

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The daily demand for ice cream cones at a price of $1.20 per cone is 50 cones. At a price of $2.20 per cone, the demand is 30 co

Lapatulllka [165]

Answer:

<h2>The demand at a price of $1.50 per cone is 44 cones</h2>

Step-by-step explanation:

let us apply the interpolation formula to solve this problem

we have

$\frac{y-y1}{x-x1} =\frac{y2-y1}{x2-x1}$

Now let us set the values to the notation above

x= $1.20

x1= $2.20

x2= $1.50

y = 50 cones

y1= 30 cones

y2= ?

$y2= \frac{(y-y1)}{(x-x1)} (x2-x1)+y1$

Substituting our given data we have

$y2= \frac{(50-30)}{(1.2-2.2)} (1.5-2.2)+30\\\\y2= \frac{20}{-1} (-0.7)+30\\\\y2= (20*0.7)+30\\y2= 14+30\\y2= 44$

the demand at a price of $1.50 per cone is 44 cones

4 0

3 years ago

Select the fraction that is equal to 2/4<br> 1/5<br> 12/7<br> 1/2

polet [3.4K]

Answer:

1/2

hope this helps

have a good day :)

Step-by-step explanation:

6 0

3 years ago

jason runs 440 yards in 75 seconds. At this rate, how many minutes does it take him to run a mile? (1 mile = 1,760 yards).

mamaluj [8]

Answer:

5 minutes

Step-by-step explanation:

we know that

Jason runs 440 yards in 75 seconds

using proportion

Find out how many minutes does it take him to run a 1.760 yards (one mile)

$\frac{440}{75}=\frac{1,760}{x}\\\\x=1,760(75)/440\\\\x= 300\ sec$

Convert seconds to minutes

Divide by 60

$300\ sec=300/60=5\ min$

8 0

3 years ago

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

3 years ago

Please answer this correctly

Firdavs [7]

Answer:

Simple:

(-2.5,-1) goes 2.5 units left and 1 units down

(0.5,2) goes half a unit right and 2 units up

Step-by-step explanation:

5 0

3 years ago