An ant looks up to the top of a tree with an angle of elevation of 38. if the ant is 43 feet from the base of the tree, what is
the height of the tree, to the nearest tenth?
a. 33.6 feet
b. 34.1 feet
c. 35.4 feet
d. 38.5 feet
a. 33.6 feet
b. 34.1 feet
c. 35.4 feet
d. 38.5 feet
2 answers:
Answer:
33.6 feet
Step-by-step explanation:
Given : An ant looks up to the top of a tree with an angle of elevation of 38.
To Find: If the ant is 43 feet from the base of the tree, what is the height of the tree, to the nearest tenth?
Solution:
Refer the attached figure
An ant looks up to the top of a tree with an angle of elevation of 38.i.e.∠ACB= 38°
The ant is 43 feet from the base of the tree i.e.BC = 43 feet.
Now we are supposed to find the height of the tree i.e. AB
Now we will use trigonometric ratio
Hence the height of the tree is 33.6 feet.
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Answer:
A = 450 cm²
Step-by-step explanation:
Since the right triangle is isosceles then the 2 logs are congruent , both 30 cm and at right angles to each other.
The area (A ) of the triangle is calculated as
A = bh ( b is the base and h the perpendicular height )
Here b = h = 30 , then
A = × 30 × 30 =
× 900 = 450 cm²
Answer:
307 paces
Step-by-step explanation:
First, lets convert Robert's pace to metres. (cm > m)
75cm = (75/100)m
= 0.75m
Number of Full Paces = Length of Bridge / 1 Full Pace
=
See , we must have full paces, and in this case we are finding the minimum number of paces, so we will be looking at the lowest possible whole number, which in this case, is 307 paces.
Given Information:
Mean time to finish 400 meter dash = μ = 65 seconds
Standard deviation to finish 400 meter dash = σ = 2.5 seconds
Confidence level = 95%
Required Information:
95% confidence interval = ?
Answer:
Step-by-step explanation:
In the normal distribution, the empirical rule states approximately 68% of all the data lie within 1 standard deviation from the mean, approximately 95% of all the data lie within 2 standard deviations from the mean and approximately 99.7% of all the data lie within 3 standard deviations from the mean.
The confidence interval for 95% confidence limit is given by
Since approximately 95% of all the data lie within 2 standard deviations from the mean. μ is the mean time Carson takes to finish 400 meter dash and σ is the standard deviation.
Therefore, the 95% confidence interval is between 60 to 70 seconds
What does it mean?
It means that we are 95% confident that the Carson's mean to finish 400 meter dash is within the interval of (60, 70).