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3 years ago

Find the equation that shows the relationship between the number of pens, p, and the

Mathematics

1 answer:

Brut [27]3 years ago

3 0

Answer: c= 0.79p

Step-by-step explanation:

Divide each cost by the number of pens it have to find the constant change value.

3.95/5 = 0.79

7.90/10= 0 .79

11.85/15 = 0.79

15.80 / 20 = 0.79

Since the constant change is 0.79 which means that for each pen it will cost you $0.79, then the equation will be c= $0.79p where c is the cost and p is the number of pens.

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Formulate the situation as a system of two linear equations in two variables. Be sure to state clearly the meaning of your x- an

adoni [48]

Answer: 1000 hot dogs and and 1600 sodas were sold.

Step-by-step explanation:

Let x be the number of hot dogs and y be the number of sodas.

Given : The concession stand at an ice hockey rink had receipts of $6200 from selling a total of 2600 sodas and hot dogs.

Each soda sold for $2 and each hot dog sold for $3 .

Then, we have the following system of two linear equations:-

$x+y=2600-----------(1)\\\\3x+2y=6200-----------(2)$

Multiplying 2 on both sides of (1), we get

$2x+2y=5200------------(3)$

Now, Eliminate equation (3) from equation (2), we get

$x=1000$

Put x=1000 in (1), we get

$1000+y=2600\\\\\Rightarrow\ y=2600-1000=1600$

Hence, 1000 hot dogs and and 1600 sodas were sold.

4 0

3 years ago

Which is the graph of f 52

Fofino [41]

There is no illustration, so it is impossible to answer this question. I apologize.

6 0

3 years ago

Find the Antilog of 547.840

bija089 [108]

Answer:

It's impossible because the figure is greater than 10

Step-by-step explanation:

${ \boxed{ \bf{antilog \: of \: x = \frac{x}{ log} = {10}^{x} }}}$

Therefore:

${ \sf{anti(547.840) = {10}^{547.840} }} \\ { \tt{ \red{math \: error \: !}}}$

3 0

3 years ago

1. (2k2+7k4+3) + (2k2-6+6k4)

stellarik [79]

Hope this will help u....:)

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4 0

3 years ago

Read 2 more answers

I have 2 more questions I still need help with sorry about me keep asking questions

algol13

I can't help I don't see a question

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3 years ago