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Mariulka [41]
3 years ago
13

Need these answered before 9:00pm tonight

Mathematics
2 answers:
yawa3891 [41]3 years ago
8 0

1. You are correct. Slope is a line's rise over its run. This line goes down 2 units for every one unit right.

2. Building off of this, you can see that for this problem, the line goes up 1 unit every 2 units right, making your slope 1/2.

3. This is a bit more confusing than the last two, so you can find the slope of the line using the slope formula. In this case, I will be using points (-5,-2) and (5,5). Slope formula is \frac{y2-y1}{x2-x1}. This becomes \frac{5-(-2)}{5-(-5)} which is \frac{7}{10}.

4. Using the points (-5,4) and (5,-4): \frac{-4-4}{5-(-5)}. This is -\frac{8}{10} and -4/5 in simplest form.

5. The line goes down 5 units every one unit to the right. Because it goes down, our slope is -5.

6. The line goes up 5 units every time it moves right once. The slope is the same as #5 except for the fact that it's positive, so it goes up.

7. The line goes down one unit every 5 units to the right, making our slope -\frac{1}{5}.

8. The line goes down 4 units every 2 units to the right, which is -4/2, although I would recommend writing it as -2.

timurjin [86]3 years ago
3 0

Answer:


Step-by-step explanation:

2)1/2


3)1


4)-1


5) -5


6)5


7)-1/5


8)-2


Please  make me brainiest

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If 5-3(2a+1)=-4a+10, what is the value of a+2​
AlekseyPX

Answer:

-2

<em>BRAINLIEST, PLEASE!</em>

Step-by-step explanation:

5 - 3(2a + 1) = -4a + 10

5 - 6a - 3 = -4a + 10

2 - 6a = -4a + 10

-2a = 8

a = -4

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3 years ago
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Write the equation of a line with a slope of 5 and contains the point (-6, 2)
tigry1 [53]
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Please assist me with the following compound interest problems.​
Sphinxa [80]

Answer:

  see the attachments below

Step-by-step explanation:

When the calculations are repetitive using the same formula, it is convenient to put the formula into a spreadsheet and let it do the calculations.

That is what was done for the spreadsheet below. The formula used is the one given in the problem statement.

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For doubling time, the formula used is the one shown in the formula bar in the attachment. (For problem 11, the quarterly value was used instead of the monthly value.) It makes use of the growth factor for the period used for the rest of the problem.

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The doubling time can also be found using a graphing calculator. In the second attachment, we have written a function that shows the multiplier for a given interest rate r and compounding n. The x-intercept in each case is the solution for t that makes the multiplier be 2. The steeper curve is associated with the higher interest rate.

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Rina8888 [55]
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Now, we can see that this is just a simple proportion problem. For every 2.5 cm of height of the flower, we are 2 cm from the opening, or aperture. For every 20 cm of height, how far are we? We can set up the problem like this:

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-------- = ---------
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where x is the unknown distance to the aperture from the flower. Now, we just need to get x by itself. A typical way of solving something like this is by doing "butterfly multiplication" which is really just a shortcut haha. Anyway, I can rewrite that equation ^ as:

20×2 = 2.5 × x

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We would then have:

20×2
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