Question

Someone please help me to solve this questions...​...

Answer 1

Answer:

1) Event A = 2/3

   Event B = 1/2

2) 1/2

Step-by-step explanation:

1)

Event A :

No. we need on dice = 4

Total numbers on dice = 6

Hence sample space of the event = 6

P( getting 4) = 4/6 = 2/3

Event B :

A coin has a head & a tail.

Hence sample space of the event = 2

But as we need tail only ,

P ( getting Tail ) = 1/2   [ if only tossed once ]

2)

Total numbers on a die = 6

Total no. of odd numbers on die = 3 (∵ 1 , 3 & 5 are odd )

Sample space of this event = 6

P (getting an odd number) = 3/6 = 1/2