33=4+7
33+11
33/11
3
12:21
=
4:7
Answer:
time = 1secs
<em>Max height = 25metres</em>
Step-by-step explanation:
Let the equation that models the height of the ball be expressed as;
h(t) = −16t^2 + 32t + 9
t is the time in seconds
The velocity of the ball at its maximum height is zero i.e dh/dt = 0
dh/dt = -32t + 32
0 = -32t + 32
32t = 32
t = 32/32
t = 1 seconds
The ball will reach its maximum height after 1 seconds.
Get the maximum height reached. Substitute t = 1 into the modeled function;
h(t) = −16t^2 + 32t + 9
h(1) = −16(1)^2 + 32(1) + 9
h(1) = −16 + 32 + 9
h(1)= 16+9
<em>h(1) = 25</em>
<em>Hence the maximum height reached is 25metres</em>
Answer:
a = 22
AB = 50
Step-by-step explanation:
Line AB=2a+6
Hope this helps
In a set of data, the mode is the most frequently observed data value. There may be no mode if no value appears more than any other. There may also be two modes (bimodal), three modes (trimodal), or four or more modes (multimodal).
