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Inga [223]
2 years ago
5

A metal frame is constructed in the form of an isosceles trapezoid. Each base angle measures 80°, the length of the base is 7 fe

et, and each of the nonparallel sides is 5 feet long. Determine the length of a diagonal brace to the nearest whole number.
Mathematics
1 answer:
jonny [76]2 years ago
3 0
Height of a trapezoid:
h = 5 · sin 80° = 5 · 0.985 = 4.924
x = 5 · cos 80° = 5 · 0.17365 = 0.868
7 - x = 7 - 0.868 = 6.132
By the Pythagorean theorem:
d² = 6.132² + 4.924²
d² = 37.6 + 24.25
d² = 61.85
d = √61.85
d = 7.86 ≈ 8
Answer: The length of a diagonal brace is 8 feet.
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<u />

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m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

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Now, the equation of the line is:

y=mx+b

We already know the slope, now we have to find the intersection point with the y-axis (b) with any of the given points. Let's choose Point 1: (x_{1},y_{1})=(0,300)

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Isolating b:

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3 years ago
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